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Integ Trans Syste 27634 pair #381739165
details
property
value
status
complete
benchmark
slayer-n2-filtered.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n099.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
4.82152080536 seconds
cpu usage
5.136527416
max memory
2.4952832E7
stage attributes
key
value
output-size
3198
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f6#(x1, x2, x3, x4, x5, x6) -> f1#(x1, x2, x3, x4, x5, x6) f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4] f3#(I18, I19, I20, I21, I22, I23) -> f2#(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2] f1#(I24, I25, I26, I27, I28, I29) -> f2#(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0] R = f6(x1, x2, x3, x4, x5, x6) -> f1(x1, x2, x3, x4, x5, x6) f5(I0, I1, I2, I3, I4, I5) -> f2(I0, I1, I2, I3, I4, I5) f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4] f2(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I17, I17) [I12 <= I14] f3(I18, I19, I20, I21, I22, I23) -> f2(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2] f1(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0] The dependency graph for this problem is: 0 -> 4 1 -> 2 2 -> 1 3 -> 2 4 -> 2 Where: 0) f6#(x1, x2, x3, x4, x5, x6) -> f1#(x1, x2, x3, x4, x5, x6) 1) f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) 2) f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4] 3) f3#(I18, I19, I20, I21, I22, I23) -> f2#(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2] 4) f1#(I24, I25, I26, I27, I28, I29) -> f2#(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f5#(I0, I1, I2, I3, I4, I5) -> f2#(I0, I1, I2, I3, I4, I5) f2#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4] R = f6(x1, x2, x3, x4, x5, x6) -> f1(x1, x2, x3, x4, x5, x6) f5(I0, I1, I2, I3, I4, I5) -> f2(I0, I1, I2, I3, I4, I5) f2(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, -1 + I8, rnd4, I10, I11) [1 + rnd4 <= I6 /\ -1 + rnd4 <= -1 + I8 /\ -1 + I8 <= -1 + rnd4 /\ 1 + I8 <= I6 /\ rnd4 = rnd4] f2(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I17, I17) [I12 <= I14] f3(I18, I19, I20, I21, I22, I23) -> f2(I18, rnd2, rnd3, I21, I22, I23) [1 + I20 <= I18 /\ y1 = -1 + I20 /\ rnd3 = rnd3 /\ -1 <= rnd3 /\ rnd3 <= -1 /\ rnd2 = rnd2 /\ rnd2 <= rnd3 /\ rnd3 <= rnd2] f1(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, 0, I27, I28, I29) [0 <= 0 /\ 0 <= 0]
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