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Integ Trans Syste 27634 pair #381739178
details
property
value
status
complete
benchmark
LinkedList.jar-obl-10.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n091.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.626673936844 seconds
cpu usage
0.659165572
max memory
1.1497472E7
stage attributes
key
value
output-size
3628
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) f2#(I0, I1, I2, I3) -> f2#(I4, I5, I2 + 4, I3) [6 <= I5 - 1 /\ 0 <= I4 - 1 /\ 0 <= I1 - 1 /\ 0 <= I0 - 1 /\ I4 <= I1 /\ I4 <= I0 /\ -1 <= I3 - 1 /\ I2 + 1 <= I3 - 1 /\ I2 + 2 <= I3 - 1] f4#(I6, I7, I8, I9) -> f4#(I10, I11, I12, I13) [-1 <= I10 - 1 /\ 0 <= I6 - 1] f3#(I14, I15, I16, I17) -> f3#(I18, I19, I20, I21) [-1 <= I18 - 1 /\ 0 <= I14 - 1] f3#(I22, I23, I24, I25) -> f4#(I26, I27, I28, I29) [-1 <= I26 - 1 /\ -1 <= I22 - 1] f2#(I30, I31, I32, I33) -> f3#(I34, I35, I36, I37) [-1 <= I34 - 1 /\ 0 <= I31 - 1 /\ I33 <= I32 /\ 0 <= I30 - 1] f1#(I38, I39, I40, I41) -> f2#(I42, I43, 1, I39) [1 <= I43 - 1 /\ 0 <= I42 - 1 /\ 0 <= I38 - 1 /\ I43 - 1 <= I38 /\ -1 <= I39 - 1 /\ I42 <= I38] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I4, I5, I2 + 4, I3) [6 <= I5 - 1 /\ 0 <= I4 - 1 /\ 0 <= I1 - 1 /\ 0 <= I0 - 1 /\ I4 <= I1 /\ I4 <= I0 /\ -1 <= I3 - 1 /\ I2 + 1 <= I3 - 1 /\ I2 + 2 <= I3 - 1] f4(I6, I7, I8, I9) -> f4(I10, I11, I12, I13) [-1 <= I10 - 1 /\ 0 <= I6 - 1] f3(I14, I15, I16, I17) -> f3(I18, I19, I20, I21) [-1 <= I18 - 1 /\ 0 <= I14 - 1] f3(I22, I23, I24, I25) -> f4(I26, I27, I28, I29) [-1 <= I26 - 1 /\ -1 <= I22 - 1] f2(I30, I31, I32, I33) -> f3(I34, I35, I36, I37) [-1 <= I34 - 1 /\ 0 <= I31 - 1 /\ I33 <= I32 /\ 0 <= I30 - 1] f1(I38, I39, I40, I41) -> f2(I42, I43, 1, I39) [1 <= I43 - 1 /\ 0 <= I42 - 1 /\ 0 <= I38 - 1 /\ I43 - 1 <= I38 /\ -1 <= I39 - 1 /\ I42 <= I38] The dependency graph for this problem is: 0 -> 6 1 -> 1, 5 2 -> 2 3 -> 3, 4 4 -> 2 5 -> 3, 4 6 -> 1, 5 Where: 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 1) f2#(I0, I1, I2, I3) -> f2#(I4, I5, I2 + 4, I3) [6 <= I5 - 1 /\ 0 <= I4 - 1 /\ 0 <= I1 - 1 /\ 0 <= I0 - 1 /\ I4 <= I1 /\ I4 <= I0 /\ -1 <= I3 - 1 /\ I2 + 1 <= I3 - 1 /\ I2 + 2 <= I3 - 1] 2) f4#(I6, I7, I8, I9) -> f4#(I10, I11, I12, I13) [-1 <= I10 - 1 /\ 0 <= I6 - 1] 3) f3#(I14, I15, I16, I17) -> f3#(I18, I19, I20, I21) [-1 <= I18 - 1 /\ 0 <= I14 - 1] 4) f3#(I22, I23, I24, I25) -> f4#(I26, I27, I28, I29) [-1 <= I26 - 1 /\ -1 <= I22 - 1] 5) f2#(I30, I31, I32, I33) -> f3#(I34, I35, I36, I37) [-1 <= I34 - 1 /\ 0 <= I31 - 1 /\ I33 <= I32 /\ 0 <= I30 - 1] 6) f1#(I38, I39, I40, I41) -> f2#(I42, I43, 1, I39) [1 <= I43 - 1 /\ 0 <= I42 - 1 /\ 0 <= I38 - 1 /\ I43 - 1 <= I38 /\ -1 <= I39 - 1 /\ I42 <= I38] We have the following SCCs. { 1 } { 3 } { 2 } DP problem for innermost termination. P = f4#(I6, I7, I8, I9) -> f4#(I10, I11, I12, I13) [-1 <= I10 - 1 /\ 0 <= I6 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I4, I5, I2 + 4, I3) [6 <= I5 - 1 /\ 0 <= I4 - 1 /\ 0 <= I1 - 1 /\ 0 <= I0 - 1 /\ I4 <= I1 /\ I4 <= I0 /\ -1 <= I3 - 1 /\ I2 + 1 <= I3 - 1 /\ I2 + 2 <= I3 - 1] f4(I6, I7, I8, I9) -> f4(I10, I11, I12, I13) [-1 <= I10 - 1 /\ 0 <= I6 - 1] f3(I14, I15, I16, I17) -> f3(I18, I19, I20, I21) [-1 <= I18 - 1 /\ 0 <= I14 - 1] f3(I22, I23, I24, I25) -> f4(I26, I27, I28, I29) [-1 <= I26 - 1 /\ -1 <= I22 - 1] f2(I30, I31, I32, I33) -> f3(I34, I35, I36, I37) [-1 <= I34 - 1 /\ 0 <= I31 - 1 /\ I33 <= I32 /\ 0 <= I30 - 1] f1(I38, I39, I40, I41) -> f2(I42, I43, 1, I39) [1 <= I43 - 1 /\ 0 <= I42 - 1 /\ 0 <= I38 - 1 /\ I43 - 1 <= I38 /\ -1 <= I39 - 1 /\ I42 <= I38]
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