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Integ Trans Syste 27634 pair #381739219
details
property
value
status
complete
benchmark
p-1.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n083.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
7.69683599472 seconds
cpu usage
8.189209263
max memory
2.5059328E7
stage attributes
key
value
output-size
2986
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4] f1#(I28, I29, I30, I31, I32, I33, I34, I35) -> f2#(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8] R = f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f2(I8, I9, I10, I11, I12, I13, I14, I15) -> f4(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4] f2(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(rnd1, I17, I18, I19, I24, I25, I22, I23) [I26 = I17 /\ I27 = I18 /\ -1 * I26 + I27 <= 0 /\ I24 = I24 /\ I25 = I25 /\ rnd1 = rnd1] f1(I28, I29, I30, I31, I32, I33, I34, I35) -> f2(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8] The dependency graph for this problem is: 0 -> 3 1 -> 2 2 -> 1 3 -> 2 Where: 0) f5#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 1) f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 2) f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4] 3) f1#(I28, I29, I30, I31, I32, I33, I34, I35) -> f2#(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f4#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f2#(I8, I9, I10, I11, I12, I13, I14, I15) -> f4#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4] R = f5(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f4(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f2(I8, I9, I10, I11, I12, I13, I14, I15) -> f4(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [y2 = I9 /\ y3 = I10 /\ 0 <= -1 - y2 + y3 /\ rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4] f2(I16, I17, I18, I19, I20, I21, I22, I23) -> f3(rnd1, I17, I18, I19, I24, I25, I22, I23) [I26 = I17 /\ I27 = I18 /\ -1 * I26 + I27 <= 0 /\ I24 = I24 /\ I25 = I25 /\ rnd1 = rnd1] f1(I28, I29, I30, I31, I32, I33, I34, I35) -> f2(I28, I29, I30, I31, I32, I33, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
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