details

property	value
status	complete
benchmark	st88b-succeed.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n110.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	11.3032341003 seconds
cpu usage	11.983879422
max memory	2.7119616E7

stage attributes

key	value
output-size	4651
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f14#(x1, x2, x3) -> f13#(x1, x2, x3) f13#(I0, I1, I2) -> f1#(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] f10#(I21, I22, I23) -> f9#(I21, I22, I23) f9#(I24, I25, I26) -> f10#(I24, I25, I26) f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] f8#(I33, I34, I35) -> f9#(I33, I34, I35) f6#(I36, I37, I38) -> f7#(I36, I37, I38) f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] f1#(I45, I46, I47) -> f2#(I45, I46, I47) R = f14(x1, x2, x3) -> f13(x1, x2, x3) f13(I0, I1, I2) -> f1(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] f3(I3, I4, I5) -> f12(I3, I4, I5) [I3 <= 5] f3(I6, I7, I8) -> f11(I6, I7, I8) [6 <= I6] f12(I9, I10, I11) -> f6(I9, I10, I11) [1 <= I11] f12(I12, I13, I14) -> f11(I12, I13, I14) [I14 <= 0] f11(I15, I16, I17) -> f2(1 + I15, I16, I17) [I15 <= 5] f11(I18, I19, I20) -> f2(1 + I18, I19, I20) [6 <= I18] f10(I21, I22, I23) -> f9(I21, I22, I23) f9(I24, I25, I26) -> f10(I24, I25, I26) f7(I27, I28, I29) -> f1(1, I28, I29) [I27 <= 2] f7(I30, I31, I32) -> f6(-1 + I30, I31, I32) [3 <= I30] f8(I33, I34, I35) -> f9(I33, I34, I35) f6(I36, I37, I38) -> f7(I36, I37, I38) f4(I39, I40, I41) -> f5(I39, I40, I41) f2(I42, I43, I44) -> f3(I42, I43, rnd3) [rnd3 = rnd3] f1(I45, I46, I47) -> f2(I45, I46, I47) The dependency graph for this problem is: 0 -> 1 1 -> 15 2 -> 4, 5 3 -> 7 4 -> 13 5 -> 6, 7 6 -> 14 7 -> 14 8 -> 9 9 -> 8 10 -> 15 11 -> 13 12 -> 9 13 -> 10, 11 14 -> 2, 3 15 -> 14 Where: 0) f14#(x1, x2, x3) -> f13#(x1, x2, x3) 1) f13#(I0, I1, I2) -> f1#(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] 2) f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] 3) f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] 4) f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] 5) f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] 6) f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] 7) f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] 8) f10#(I21, I22, I23) -> f9#(I21, I22, I23) 9) f9#(I24, I25, I26) -> f10#(I24, I25, I26) 10) f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] 11) f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] 12) f8#(I33, I34, I35) -> f9#(I33, I34, I35) 13) f6#(I36, I37, I38) -> f7#(I36, I37, I38) 14) f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] 15) f1#(I45, I46, I47) -> f2#(I45, I46, I47) We have the following SCCs. { 8, 9 } { 2, 3, 4, 5, 6, 7, 10, 11, 13, 14, 15 } DP problem for innermost termination. P = f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] f6#(I36, I37, I38) -> f7#(I36, I37, I38) f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] f1#(I45, I46, I47) -> f2#(I45, I46, I47) R = f14(x1, x2, x3) -> f13(x1, x2, x3) f13(I0, I1, I2) -> f1(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integ Trans Syste 27634