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Integ Trans Syste 27634 pair #381739504
details
property
value
status
complete
benchmark
l1.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n024.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.82574605942 seconds
cpu usage
1.931631826
max memory
1.7350656E7
stage attributes
key
value
output-size
2014
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f4#(x1, x2, x3) -> f3#(x1, x2, x3) f3#(I0, I1, I2) -> f1#(rnd1, I1, I2) [y1 = -1 /\ y2 = -1 + y1 /\ y3 = -1 + y2 /\ y4 = -1 + y3 /\ y5 = -1 + y4 /\ y6 = -1 + y5 /\ y7 = -1 + y6 /\ y8 = -1 + y7 /\ y9 = -1 + y8 /\ rnd1 = -1 + y9 /\ -1 <= I1 /\ rnd1 <= I2] f2#(I3, I4, I5) -> f1#(I3, I4, I5) f1#(I6, I7, I8) -> f2#(I6, I7 + I8, I8) [I6 <= I8 /\ 0 <= I7] R = f4(x1, x2, x3) -> f3(x1, x2, x3) f3(I0, I1, I2) -> f1(rnd1, I1, I2) [y1 = -1 /\ y2 = -1 + y1 /\ y3 = -1 + y2 /\ y4 = -1 + y3 /\ y5 = -1 + y4 /\ y6 = -1 + y5 /\ y7 = -1 + y6 /\ y8 = -1 + y7 /\ y9 = -1 + y8 /\ rnd1 = -1 + y9 /\ -1 <= I1 /\ rnd1 <= I2] f2(I3, I4, I5) -> f1(I3, I4, I5) f1(I6, I7, I8) -> f2(I6, I7 + I8, I8) [I6 <= I8 /\ 0 <= I7] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1, x2, x3) -> f3#(x1, x2, x3) 1) f3#(I0, I1, I2) -> f1#(rnd1, I1, I2) [y1 = -1 /\ y2 = -1 + y1 /\ y3 = -1 + y2 /\ y4 = -1 + y3 /\ y5 = -1 + y4 /\ y6 = -1 + y5 /\ y7 = -1 + y6 /\ y8 = -1 + y7 /\ y9 = -1 + y8 /\ rnd1 = -1 + y9 /\ -1 <= I1 /\ rnd1 <= I2] 2) f2#(I3, I4, I5) -> f1#(I3, I4, I5) 3) f1#(I6, I7, I8) -> f2#(I6, I7 + I8, I8) [I6 <= I8 /\ 0 <= I7] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I3, I4, I5) -> f1#(I3, I4, I5) f1#(I6, I7, I8) -> f2#(I6, I7 + I8, I8) [I6 <= I8 /\ 0 <= I7] R = f4(x1, x2, x3) -> f3(x1, x2, x3) f3(I0, I1, I2) -> f1(rnd1, I1, I2) [y1 = -1 /\ y2 = -1 + y1 /\ y3 = -1 + y2 /\ y4 = -1 + y3 /\ y5 = -1 + y4 /\ y6 = -1 + y5 /\ y7 = -1 + y6 /\ y8 = -1 + y7 /\ y9 = -1 + y8 /\ rnd1 = -1 + y9 /\ -1 <= I1 /\ rnd1 <= I2] f2(I3, I4, I5) -> f1(I3, I4, I5) f1(I6, I7, I8) -> f2(I6, I7 + I8, I8) [I6 <= I8 /\ 0 <= I7]
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