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Integ Trans Syste 27634 pair #381739516
details
property
value
status
complete
benchmark
polyrank7.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n090.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.13162899017 seconds
cpu usage
2.252078632
max memory
1.8833408E7
stage attributes
key
value
output-size
1774
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f5#(x1, x2, x3) -> f4#(x1, x2, x3) f4#(I0, I1, I2) -> f1#(I0, I1, I2) [0 <= I0] f3#(I3, I4, I5) -> f1#(I3, I4, I5) f1#(I6, I7, I8) -> f3#(I6 + I8, 1 + I7, -2 + I8) f2#(I9, I10, I11) -> f1#(I9, I10, I11) f1#(I12, I13, I14) -> f2#(I12 + I13, -2 + I13, I14) R = f5(x1, x2, x3) -> f4(x1, x2, x3) f4(I0, I1, I2) -> f1(I0, I1, I2) [0 <= I0] f3(I3, I4, I5) -> f1(I3, I4, I5) f1(I6, I7, I8) -> f3(I6 + I8, 1 + I7, -2 + I8) f2(I9, I10, I11) -> f1(I9, I10, I11) f1(I12, I13, I14) -> f2(I12 + I13, -2 + I13, I14) The dependency graph for this problem is: 0 -> 1 1 -> 3, 5 2 -> 3, 5 3 -> 2 4 -> 3, 5 5 -> 4 Where: 0) f5#(x1, x2, x3) -> f4#(x1, x2, x3) 1) f4#(I0, I1, I2) -> f1#(I0, I1, I2) [0 <= I0] 2) f3#(I3, I4, I5) -> f1#(I3, I4, I5) 3) f1#(I6, I7, I8) -> f3#(I6 + I8, 1 + I7, -2 + I8) 4) f2#(I9, I10, I11) -> f1#(I9, I10, I11) 5) f1#(I12, I13, I14) -> f2#(I12 + I13, -2 + I13, I14) We have the following SCCs. { 2, 3, 4, 5 } DP problem for innermost termination. P = f3#(I3, I4, I5) -> f1#(I3, I4, I5) f1#(I6, I7, I8) -> f3#(I6 + I8, 1 + I7, -2 + I8) f2#(I9, I10, I11) -> f1#(I9, I10, I11) f1#(I12, I13, I14) -> f2#(I12 + I13, -2 + I13, I14) R = f5(x1, x2, x3) -> f4(x1, x2, x3) f4(I0, I1, I2) -> f1(I0, I1, I2) [0 <= I0] f3(I3, I4, I5) -> f1(I3, I4, I5) f1(I6, I7, I8) -> f3(I6 + I8, 1 + I7, -2 + I8) f2(I9, I10, I11) -> f1(I9, I10, I11) f1(I12, I13, I14) -> f2(I12 + I13, -2 + I13, I14)
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