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Integ Trans Syste 27634 pair #381739531
details
property
value
status
complete
benchmark
e-smagill-succeed.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n023.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.88817191124 seconds
cpu usage
3.060648968
max memory
2.332672E7
stage attributes
key
value
output-size
3495
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5) -> f8#(x1, x2, x3, x4, x5) f8#(I0, I1, I2, I3, I4) -> f1#(I0, rnd2, rnd3, 0, 4) [rnd3 = 4 /\ 1 <= rnd2 /\ rnd2 = rnd2] f2#(I5, I6, I7, I8, I9) -> f5#(I5, I6, I7, I8, I9) [I7 <= 0] f2#(I10, I11, I12, I13, I14) -> f7#(rnd1, I11, I12, I13, I14) [rnd1 = rnd1 /\ 1 <= I12] f7#(I15, I16, I17, I18, I19) -> f1#(I15, -1 + I16, -1 + I17, 1 + I18, I19) [1 <= I15] f7#(I20, I21, I22, I23, I24) -> f1#(I20, I21, -1 + I22, I23, I24) [1 + I21 <= I22 /\ I20 <= 0] f6#(I25, I26, I27, I28, I29) -> f5#(I25, I26, I27, I28, I29) f5#(I30, I31, I32, I33, I34) -> f6#(I30, I31, I32, I33, I34) f1#(I40, I41, I42, I43, I44) -> f2#(I40, I41, I42, I43, I44) R = f9(x1, x2, x3, x4, x5) -> f8(x1, x2, x3, x4, x5) f8(I0, I1, I2, I3, I4) -> f1(I0, rnd2, rnd3, 0, 4) [rnd3 = 4 /\ 1 <= rnd2 /\ rnd2 = rnd2] f2(I5, I6, I7, I8, I9) -> f5(I5, I6, I7, I8, I9) [I7 <= 0] f2(I10, I11, I12, I13, I14) -> f7(rnd1, I11, I12, I13, I14) [rnd1 = rnd1 /\ 1 <= I12] f7(I15, I16, I17, I18, I19) -> f1(I15, -1 + I16, -1 + I17, 1 + I18, I19) [1 <= I15] f7(I20, I21, I22, I23, I24) -> f1(I20, I21, -1 + I22, I23, I24) [1 + I21 <= I22 /\ I20 <= 0] f6(I25, I26, I27, I28, I29) -> f5(I25, I26, I27, I28, I29) f5(I30, I31, I32, I33, I34) -> f6(I30, I31, I32, I33, I34) f3(I35, I36, I37, I38, I39) -> f4(I35, I36, I37, I38, I39) f1(I40, I41, I42, I43, I44) -> f2(I40, I41, I42, I43, I44) The dependency graph for this problem is: 0 -> 1 1 -> 8 2 -> 7 3 -> 4, 5 4 -> 8 5 -> 8 6 -> 7 7 -> 6 8 -> 2, 3 Where: 0) f9#(x1, x2, x3, x4, x5) -> f8#(x1, x2, x3, x4, x5) 1) f8#(I0, I1, I2, I3, I4) -> f1#(I0, rnd2, rnd3, 0, 4) [rnd3 = 4 /\ 1 <= rnd2 /\ rnd2 = rnd2] 2) f2#(I5, I6, I7, I8, I9) -> f5#(I5, I6, I7, I8, I9) [I7 <= 0] 3) f2#(I10, I11, I12, I13, I14) -> f7#(rnd1, I11, I12, I13, I14) [rnd1 = rnd1 /\ 1 <= I12] 4) f7#(I15, I16, I17, I18, I19) -> f1#(I15, -1 + I16, -1 + I17, 1 + I18, I19) [1 <= I15] 5) f7#(I20, I21, I22, I23, I24) -> f1#(I20, I21, -1 + I22, I23, I24) [1 + I21 <= I22 /\ I20 <= 0] 6) f6#(I25, I26, I27, I28, I29) -> f5#(I25, I26, I27, I28, I29) 7) f5#(I30, I31, I32, I33, I34) -> f6#(I30, I31, I32, I33, I34) 8) f1#(I40, I41, I42, I43, I44) -> f2#(I40, I41, I42, I43, I44) We have the following SCCs. { 3, 4, 5, 8 } { 6, 7 } DP problem for innermost termination. P = f6#(I25, I26, I27, I28, I29) -> f5#(I25, I26, I27, I28, I29) f5#(I30, I31, I32, I33, I34) -> f6#(I30, I31, I32, I33, I34) R = f9(x1, x2, x3, x4, x5) -> f8(x1, x2, x3, x4, x5) f8(I0, I1, I2, I3, I4) -> f1(I0, rnd2, rnd3, 0, 4) [rnd3 = 4 /\ 1 <= rnd2 /\ rnd2 = rnd2] f2(I5, I6, I7, I8, I9) -> f5(I5, I6, I7, I8, I9) [I7 <= 0] f2(I10, I11, I12, I13, I14) -> f7(rnd1, I11, I12, I13, I14) [rnd1 = rnd1 /\ 1 <= I12] f7(I15, I16, I17, I18, I19) -> f1(I15, -1 + I16, -1 + I17, 1 + I18, I19) [1 <= I15] f7(I20, I21, I22, I23, I24) -> f1(I20, I21, -1 + I22, I23, I24) [1 + I21 <= I22 /\ I20 <= 0] f6(I25, I26, I27, I28, I29) -> f5(I25, I26, I27, I28, I29) f5(I30, I31, I32, I33, I34) -> f6(I30, I31, I32, I33, I34) f3(I35, I36, I37, I38, I39) -> f4(I35, I36, I37, I38, I39) f1(I40, I41, I42, I43, I44) -> f2(I40, I41, I42, I43, I44)
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