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Integ Trans Syste 27634 pair #381739627
details
property
value
status
complete
benchmark
p-52.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n033.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
11.9989891052 seconds
cpu usage
12.805187157
max memory
2.8041216E7
stage attributes
key
value
output-size
3572
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1#(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8, rnd9, rnd10) [rnd8 = rnd6 /\ rnd7 = rnd10 /\ rnd10 = rnd10 /\ rnd9 = rnd9 /\ rnd6 = rnd6] f2#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) f1#(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2#(I30, I31, rnd3, I40, I41, I35, I36, I37, I38, I39) [I42 = I38 /\ y3 = I31 /\ 0 <= -1 + y3 /\ I40 = I40 /\ I41 = I41 /\ I43 = I31 /\ rnd3 = rnd3] R = f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8, rnd9, rnd10) [rnd8 = rnd6 /\ rnd7 = rnd10 /\ rnd10 = rnd10 /\ rnd9 = rnd9 /\ rnd6 = rnd6] f1(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f3(rnd1, I11, I12, rnd4, rnd5, I15, I16, I17, I18, I19) [y1 = I18 /\ y2 = I11 /\ y2 <= 0 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ rnd1 = rnd1] f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f1(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) f1(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2(I30, I31, rnd3, I40, I41, I35, I36, I37, I38, I39) [I42 = I38 /\ y3 = I31 /\ 0 <= -1 + y3 /\ I40 = I40 /\ I41 = I41 /\ I43 = I31 /\ rnd3 = rnd3] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 1) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1#(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8, rnd9, rnd10) [rnd8 = rnd6 /\ rnd7 = rnd10 /\ rnd10 = rnd10 /\ rnd9 = rnd9 /\ rnd6 = rnd6] 2) f2#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) 3) f1#(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2#(I30, I31, rnd3, I40, I41, I35, I36, I37, I38, I39) [I42 = I38 /\ y3 = I31 /\ 0 <= -1 + y3 /\ I40 = I40 /\ I41 = I41 /\ I43 = I31 /\ rnd3 = rnd3] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) f1#(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2#(I30, I31, rnd3, I40, I41, I35, I36, I37, I38, I39) [I42 = I38 /\ y3 = I31 /\ 0 <= -1 + y3 /\ I40 = I40 /\ I41 = I41 /\ I43 = I31 /\ rnd3 = rnd3] R = f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1(I0, I1, I2, I3, I4, rnd6, rnd7, rnd8, rnd9, rnd10) [rnd8 = rnd6 /\ rnd7 = rnd10 /\ rnd10 = rnd10 /\ rnd9 = rnd9 /\ rnd6 = rnd6] f1(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f3(rnd1, I11, I12, rnd4, rnd5, I15, I16, I17, I18, I19) [y1 = I18 /\ y2 = I11 /\ y2 <= 0 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ rnd1 = rnd1] f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f1(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) f1(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2(I30, I31, rnd3, I40, I41, I35, I36, I37, I38, I39) [I42 = I38 /\ y3 = I31 /\ 0 <= -1 + y3 /\ I40 = I40 /\ I41 = I41 /\ I43 = I31 /\ rnd3 = rnd3]
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