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Integ Trans Syste 27634 pair #381739633
details
property
value
status
complete
benchmark
matmul.t2_fixed.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n016.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
17.4901309013 seconds
cpu usage
18.549056414
max memory
2.4584192E7
stage attributes
key
value
output-size
17412
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f13#(x1, x2, x3) -> f12#(x1, x2, x3) f12#(I0, I1, I2) -> f1#(1, I1, I2) f2#(I3, I4, I5) -> f3#(I3, 1, I5) [I3 <= 5] f2#(I6, I7, I8) -> f5#(1, I7, I8) [6 <= I6] f4#(I9, I10, I11) -> f3#(I9, 1 + I10, I11) [I10 <= 5] f4#(I12, I13, I14) -> f1#(1 + I12, I13, I14) [6 <= I13] f10#(I15, I16, I17) -> f9#(I15, I16, I17) f6#(I18, I19, I20) -> f7#(I18, 1, I20) [I18 <= 5] f8#(I24, I25, I26) -> f10#(I24, I25, 1) [I25 <= 5] f8#(I27, I28, I29) -> f5#(1 + I27, I28, I29) [6 <= I28] f9#(I30, I31, I32) -> f10#(I30, I31, 1 + I32) [I32 <= 5] f9#(I33, I34, I35) -> f7#(I33, 1 + I34, I35) [6 <= I35] f7#(I36, I37, I38) -> f8#(I36, I37, I38) f5#(I39, I40, I41) -> f6#(I39, I40, I41) f3#(I42, I43, I44) -> f4#(I42, I43, I44) f1#(I45, I46, I47) -> f2#(I45, I46, I47) R = f13(x1, x2, x3) -> f12(x1, x2, x3) f12(I0, I1, I2) -> f1(1, I1, I2) f2(I3, I4, I5) -> f3(I3, 1, I5) [I3 <= 5] f2(I6, I7, I8) -> f5(1, I7, I8) [6 <= I6] f4(I9, I10, I11) -> f3(I9, 1 + I10, I11) [I10 <= 5] f4(I12, I13, I14) -> f1(1 + I12, I13, I14) [6 <= I13] f10(I15, I16, I17) -> f9(I15, I16, I17) f6(I18, I19, I20) -> f7(I18, 1, I20) [I18 <= 5] f6(I21, I22, I23) -> f11(I21, I22, I23) [6 <= I21] f8(I24, I25, I26) -> f10(I24, I25, 1) [I25 <= 5] f8(I27, I28, I29) -> f5(1 + I27, I28, I29) [6 <= I28] f9(I30, I31, I32) -> f10(I30, I31, 1 + I32) [I32 <= 5] f9(I33, I34, I35) -> f7(I33, 1 + I34, I35) [6 <= I35] f7(I36, I37, I38) -> f8(I36, I37, I38) f5(I39, I40, I41) -> f6(I39, I40, I41) f3(I42, I43, I44) -> f4(I42, I43, I44) f1(I45, I46, I47) -> f2(I45, I46, I47) The dependency graph for this problem is: 0 -> 1 1 -> 15 2 -> 14 3 -> 13 4 -> 14 5 -> 15 6 -> 10, 11 7 -> 12 8 -> 6 9 -> 13 10 -> 6 11 -> 12 12 -> 8, 9 13 -> 7 14 -> 4, 5 15 -> 2, 3 Where: 0) f13#(x1, x2, x3) -> f12#(x1, x2, x3) 1) f12#(I0, I1, I2) -> f1#(1, I1, I2) 2) f2#(I3, I4, I5) -> f3#(I3, 1, I5) [I3 <= 5] 3) f2#(I6, I7, I8) -> f5#(1, I7, I8) [6 <= I6] 4) f4#(I9, I10, I11) -> f3#(I9, 1 + I10, I11) [I10 <= 5] 5) f4#(I12, I13, I14) -> f1#(1 + I12, I13, I14) [6 <= I13] 6) f10#(I15, I16, I17) -> f9#(I15, I16, I17) 7) f6#(I18, I19, I20) -> f7#(I18, 1, I20) [I18 <= 5] 8) f8#(I24, I25, I26) -> f10#(I24, I25, 1) [I25 <= 5] 9) f8#(I27, I28, I29) -> f5#(1 + I27, I28, I29) [6 <= I28] 10) f9#(I30, I31, I32) -> f10#(I30, I31, 1 + I32) [I32 <= 5] 11) f9#(I33, I34, I35) -> f7#(I33, 1 + I34, I35) [6 <= I35] 12) f7#(I36, I37, I38) -> f8#(I36, I37, I38) 13) f5#(I39, I40, I41) -> f6#(I39, I40, I41) 14) f3#(I42, I43, I44) -> f4#(I42, I43, I44) 15) f1#(I45, I46, I47) -> f2#(I45, I46, I47) We have the following SCCs. { 2, 4, 5, 14, 15 } { 6, 7, 8, 9, 10, 11, 12, 13 } DP problem for innermost termination. P = f10#(I15, I16, I17) -> f9#(I15, I16, I17) f6#(I18, I19, I20) -> f7#(I18, 1, I20) [I18 <= 5] f8#(I24, I25, I26) -> f10#(I24, I25, 1) [I25 <= 5] f8#(I27, I28, I29) -> f5#(1 + I27, I28, I29) [6 <= I28] f9#(I30, I31, I32) -> f10#(I30, I31, 1 + I32) [I32 <= 5] f9#(I33, I34, I35) -> f7#(I33, 1 + I34, I35) [6 <= I35] f7#(I36, I37, I38) -> f8#(I36, I37, I38) f5#(I39, I40, I41) -> f6#(I39, I40, I41) R = f13(x1, x2, x3) -> f12(x1, x2, x3) f12(I0, I1, I2) -> f1(1, I1, I2) f2(I3, I4, I5) -> f3(I3, 1, I5) [I3 <= 5] f2(I6, I7, I8) -> f5(1, I7, I8) [6 <= I6] f4(I9, I10, I11) -> f3(I9, 1 + I10, I11) [I10 <= 5]
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