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Integ Trans Syste 27634 pair #381740023
details
property
value
status
complete
benchmark
ex40.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n109.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.854942083359 seconds
cpu usage
0.895158349
max memory
1.2832768E7
stage attributes
key
value
output-size
2770
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f10#(x1, x2) -> f9#(x1, x2) f9#(I0, I1) -> f2#(0, rnd2) [rnd2 = rnd2] f4#(I2, I3) -> f8#(I2, I3) [0 <= I3] f4#(I4, I5) -> f5#(I4, I5) [1 + I5 <= 0] f8#(I6, I7) -> f7#(I6, I7) [1 + I7 <= I6] f8#(I8, I9) -> f5#(I8, I9) [I8 <= I9] f7#(I12, I13) -> f5#(I12, I13) f7#(I14, I15) -> f5#(I14, I15) f2#(I18, I19) -> f3#(I18, I19) f3#(I20, I21) -> f4#(I20, I21) f3#(I22, I23) -> f1#(I22, I23) f3#(I24, I25) -> f1#(I24, I25) f1#(I26, I27) -> f2#(1 + I26, I27) R = f10(x1, x2) -> f9(x1, x2) f9(I0, I1) -> f2(0, rnd2) [rnd2 = rnd2] f4(I2, I3) -> f8(I2, I3) [0 <= I3] f4(I4, I5) -> f5(I4, I5) [1 + I5 <= 0] f8(I6, I7) -> f7(I6, I7) [1 + I7 <= I6] f8(I8, I9) -> f5(I8, I9) [I8 <= I9] f7(I10, I11) -> f6(I10, I11) f7(I12, I13) -> f5(I12, I13) f7(I14, I15) -> f5(I14, I15) f5(I16, I17) -> f6(I16, I17) f2(I18, I19) -> f3(I18, I19) f3(I20, I21) -> f4(I20, I21) f3(I22, I23) -> f1(I22, I23) f3(I24, I25) -> f1(I24, I25) f1(I26, I27) -> f2(1 + I26, I27) The dependency graph for this problem is: 0 -> 1 1 -> 8 2 -> 4, 5 3 -> 4 -> 6, 7 5 -> 6 -> 7 -> 8 -> 9, 10, 11 9 -> 2, 3 10 -> 12 11 -> 12 12 -> 8 Where: 0) f10#(x1, x2) -> f9#(x1, x2) 1) f9#(I0, I1) -> f2#(0, rnd2) [rnd2 = rnd2] 2) f4#(I2, I3) -> f8#(I2, I3) [0 <= I3] 3) f4#(I4, I5) -> f5#(I4, I5) [1 + I5 <= 0] 4) f8#(I6, I7) -> f7#(I6, I7) [1 + I7 <= I6] 5) f8#(I8, I9) -> f5#(I8, I9) [I8 <= I9] 6) f7#(I12, I13) -> f5#(I12, I13) 7) f7#(I14, I15) -> f5#(I14, I15) 8) f2#(I18, I19) -> f3#(I18, I19) 9) f3#(I20, I21) -> f4#(I20, I21) 10) f3#(I22, I23) -> f1#(I22, I23) 11) f3#(I24, I25) -> f1#(I24, I25) 12) f1#(I26, I27) -> f2#(1 + I26, I27) We have the following SCCs. { 8, 10, 11, 12 } DP problem for innermost termination. P = f2#(I18, I19) -> f3#(I18, I19) f3#(I22, I23) -> f1#(I22, I23) f3#(I24, I25) -> f1#(I24, I25) f1#(I26, I27) -> f2#(1 + I26, I27) R = f10(x1, x2) -> f9(x1, x2) f9(I0, I1) -> f2(0, rnd2) [rnd2 = rnd2] f4(I2, I3) -> f8(I2, I3) [0 <= I3] f4(I4, I5) -> f5(I4, I5) [1 + I5 <= 0] f8(I6, I7) -> f7(I6, I7) [1 + I7 <= I6] f8(I8, I9) -> f5(I8, I9) [I8 <= I9] f7(I10, I11) -> f6(I10, I11) f7(I12, I13) -> f5(I12, I13) f7(I14, I15) -> f5(I14, I15) f5(I16, I17) -> f6(I16, I17) f2(I18, I19) -> f3(I18, I19) f3(I20, I21) -> f4(I20, I21) f3(I22, I23) -> f1(I22, I23) f3(I24, I25) -> f1(I24, I25) f1(I26, I27) -> f2(1 + I26, I27)
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