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Integ Trans Syste 27634 pair #381740032
details
property
value
status
complete
benchmark
ex2.t2_fixed.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n190.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.95857095718 seconds
cpu usage
2.071216009
max memory
1.8194432E7
stage attributes
key
value
output-size
2962
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f8#(x1, x2, x3, x4) -> f7#(x1, x2, x3, x4) f7#(I0, I1, I2, I3) -> f4#(I0, rnd2, rnd3, I3) [rnd2 = rnd3 /\ rnd3 = rnd3] f5#(I4, I5, I6, I7) -> f3#(1 + I4, I5, I6, I7) f3#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) f4#(I16, I17, I18, I19) -> f2#(I16, I17, I18, I19) [I17 <= 0] f4#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) [1 <= I21] f2#(I24, I25, I26, I27) -> f3#(0, I25, I26, I27) f1#(I28, I29, I30, I31) -> f2#(I28, I29, I30, I31) [1024 <= I29] f1#(I32, I33, I34, I35) -> f2#(I32, I33, I34, rnd4) [rnd4 = rnd4 /\ 1 + I33 <= 1024] R = f8(x1, x2, x3, x4) -> f7(x1, x2, x3, x4) f7(I0, I1, I2, I3) -> f4(I0, rnd2, rnd3, I3) [rnd2 = rnd3 /\ rnd3 = rnd3] f5(I4, I5, I6, I7) -> f3(1 + I4, I5, I6, I7) f5(I8, I9, I10, I11) -> f6(I8, I9, I10, I11) f3(I12, I13, I14, I15) -> f5(I12, I13, I14, I15) f4(I16, I17, I18, I19) -> f2(I16, I17, I18, I19) [I17 <= 0] f4(I20, I21, I22, I23) -> f1(I20, I21, I22, I23) [1 <= I21] f2(I24, I25, I26, I27) -> f3(0, I25, I26, I27) f1(I28, I29, I30, I31) -> f2(I28, I29, I30, I31) [1024 <= I29] f1(I32, I33, I34, I35) -> f2(I32, I33, I34, rnd4) [rnd4 = rnd4 /\ 1 + I33 <= 1024] The dependency graph for this problem is: 0 -> 1 1 -> 4, 5 2 -> 3 3 -> 2 4 -> 6 5 -> 7, 8 6 -> 3 7 -> 6 8 -> 6 Where: 0) f8#(x1, x2, x3, x4) -> f7#(x1, x2, x3, x4) 1) f7#(I0, I1, I2, I3) -> f4#(I0, rnd2, rnd3, I3) [rnd2 = rnd3 /\ rnd3 = rnd3] 2) f5#(I4, I5, I6, I7) -> f3#(1 + I4, I5, I6, I7) 3) f3#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) 4) f4#(I16, I17, I18, I19) -> f2#(I16, I17, I18, I19) [I17 <= 0] 5) f4#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) [1 <= I21] 6) f2#(I24, I25, I26, I27) -> f3#(0, I25, I26, I27) 7) f1#(I28, I29, I30, I31) -> f2#(I28, I29, I30, I31) [1024 <= I29] 8) f1#(I32, I33, I34, I35) -> f2#(I32, I33, I34, rnd4) [rnd4 = rnd4 /\ 1 + I33 <= 1024] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f5#(I4, I5, I6, I7) -> f3#(1 + I4, I5, I6, I7) f3#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) R = f8(x1, x2, x3, x4) -> f7(x1, x2, x3, x4) f7(I0, I1, I2, I3) -> f4(I0, rnd2, rnd3, I3) [rnd2 = rnd3 /\ rnd3 = rnd3] f5(I4, I5, I6, I7) -> f3(1 + I4, I5, I6, I7) f5(I8, I9, I10, I11) -> f6(I8, I9, I10, I11) f3(I12, I13, I14, I15) -> f5(I12, I13, I14, I15) f4(I16, I17, I18, I19) -> f2(I16, I17, I18, I19) [I17 <= 0] f4(I20, I21, I22, I23) -> f1(I20, I21, I22, I23) [1 <= I21] f2(I24, I25, I26, I27) -> f3(0, I25, I26, I27) f1(I28, I29, I30, I31) -> f2(I28, I29, I30, I31) [1024 <= I29] f1(I32, I33, I34, I35) -> f2(I32, I33, I34, rnd4) [rnd4 = rnd4 /\ 1 + I33 <= 1024]
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