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Integ Trans Syste 27634 pair #381740197
details
property
value
status
complete
benchmark
refine_disj_problem.t2_fixed.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n038.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.95099282265 seconds
cpu usage
2.067479731
max memory
1.837056E7
stage attributes
key
value
output-size
1693
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f6#(x1, x2) -> f1#(x1, x2) f5#(I0, I1) -> f2#(I0, I1) f4#(I2, I3) -> f5#(I2 + I3, I3) f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] f1#(I10, I11) -> f2#(I10, I11) R = f6(x1, x2) -> f1(x1, x2) f5(I0, I1) -> f2(I0, I1) f4(I2, I3) -> f5(I2 + I3, I3) f3(I4, I5) -> f4(I4, I5) [1 <= I5] f3(I6, I7) -> f4(I6, I7) [1 + I7 <= 0] f2(I8, I9) -> f3(I8, I9) [1 <= I8] f1(I10, I11) -> f2(I10, I11) The dependency graph for this problem is: 0 -> 6 1 -> 5 2 -> 1 3 -> 2 4 -> 2 5 -> 3, 4 6 -> 5 Where: 0) f6#(x1, x2) -> f1#(x1, x2) 1) f5#(I0, I1) -> f2#(I0, I1) 2) f4#(I2, I3) -> f5#(I2 + I3, I3) 3) f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] 4) f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] 5) f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] 6) f1#(I10, I11) -> f2#(I10, I11) We have the following SCCs. { 1, 2, 3, 4, 5 } DP problem for innermost termination. P = f5#(I0, I1) -> f2#(I0, I1) f4#(I2, I3) -> f5#(I2 + I3, I3) f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] R = f6(x1, x2) -> f1(x1, x2) f5(I0, I1) -> f2(I0, I1) f4(I2, I3) -> f5(I2 + I3, I3) f3(I4, I5) -> f4(I4, I5) [1 <= I5] f3(I6, I7) -> f4(I6, I7) [1 + I7 <= 0] f2(I8, I9) -> f3(I8, I9) [1 <= I8] f1(I10, I11) -> f2(I10, I11)
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