details

property	value
status	complete
benchmark	bitcount16.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n054.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	36.3471620083 seconds
cpu usage	38.663093499
max memory	4.2364928E7

stage attributes

key	value
output-size	7827
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f7#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f6#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f6#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2#(0, I3, I2, I3, I4, 0, I6, I7, I8, I9, I10) f2#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f4#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] f3#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1#(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3#(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1#(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) R = f7(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f6(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2(0, I3, I2, I3, I4, 0, I6, I7, I8, I9, I10) f2(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f4(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] f4(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f5(I33, I34, I36, I36, rnd5, I38, I38, rnd8, I41, I38, rnd11) [16 <= I33 /\ y1 = I36 /\ y2 = y2 /\ y3 = y3 /\ y4 = y4 /\ rnd5 = rnd5 /\ rnd8 = rnd5 /\ rnd11 = rnd8] f3(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) The dependency graph for this problem is: 0 -> 1 1 -> 2 2 -> 3 3 -> 4, 5 4 -> 6 5 -> 6 6 -> 2 Where: 0) f7#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f6#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 1) f6#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2#(0, I3, I2, I3, I4, 0, I6, I7, I8, I9, I10) 2) f2#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) 3) f4#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] 4) f3#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1#(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) 5) f3#(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1#(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) 6) f1#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) We have the following SCCs. { 2, 3, 4, 5, 6 } DP problem for innermost termination. P = f2#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f4#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] f3#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1#(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3#(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1#(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) R = f7(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f6(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2(0, I3, I2, I3, I4, 0, I6, I7, I8, I9, I10) f2(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f4(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] f4(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f5(I33, I34, I36, I36, rnd5, I38, I38, rnd8, I41, I38, rnd11) [16 <= I33 /\ y1 = I36 /\ y2 = y2 /\ y3 = y3 /\ y4 = y4 /\ rnd5 = rnd5 /\ rnd8 = rnd5 /\ rnd11 = rnd8] f3(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) We use the extended value criterion with the projection function NU: NU[f1#(x0,x1,x2,x3,x4,x5,x6,x7,x8,x9,x10)] = -x0 + 14 NU[f3#(x0,x1,x2,x3,x4,x5,x6,x7,x8,x9,x10)] = -x0 + 14 NU[f4#(x0,x1,x2,x3,x4,x5,x6,x7,x8,x9,x10)] = -x0 + 15 NU[f2#(x0,x1,x2,x3,x4,x5,x6,x7,x8,x9,x10)] = -x0 + 15 This gives the following inequalities: ==> -I11 + 15 >= -I11 + 15 1 + I22 <= 16 ==> -I22 + 15 > -I22 + 14 with -I22 + 15 >= 0 ==> -I44 + 14 >= -I44 + 14 ==> -I55 + 14 >= -I55 + 14 ==> -I66 + 14 >= -(1 + I66) + 15 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f2#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f3#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1#(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3#(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1#(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) R = f7(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f6(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f2(0, I3, I2, I3, I4, 0, I6, I7, I8, I9, I10) f2(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f4(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) f4(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) [1 + I22 <= 16] f4(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f5(I33, I34, I36, I36, rnd5, I38, I38, rnd8, I41, I38, rnd11) [16 <= I33 /\ y1 = I36 /\ y2 = y2 /\ y3 = y3 /\ y4 = y4 /\ rnd5 = rnd5 /\ rnd8 = rnd5 /\ rnd11 = rnd8] f3(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f1(I44, I45, I46, I47, I48, I49, I50, I51, 1, I53, I54) f3(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f1(I55, I56, I57, I58, I59, I60, I61, I62, 0, I64, I65) f1(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(1 + I66, I67, I68, I69, I70, I71 + I74, I72, I73, I74, I75, I76) The dependency graph for this problem is: 2 -> 4 -> 6 5 -> 6 6 -> 2 popout

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all output return to Integ Trans Syste 27634