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Integ Trans Syste 27634 pair #381740350
details
property
value
status
complete
benchmark
ex31.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n081.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.52395892143 seconds
cpu usage
2.668661008
max memory
2.0164608E7
stage attributes
key
value
output-size
1927
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f6#(x1, x2, x3) -> f5#(x1, x2, x3) f5#(I0, I1, I2) -> f2#(I0, 0, I0) f2#(I3, I4, I5) -> f3#(I3, I4, I5) f3#(I6, I7, I8) -> f1#(I6, I7, I8) [1 + I7 <= I8] f1#(I12, I13, I14) -> f2#(I12, I13, rnd3) [rnd3 = rnd3] f1#(I15, I16, I17) -> f2#(I15, rnd2, I17) [rnd2 = rnd2] R = f6(x1, x2, x3) -> f5(x1, x2, x3) f5(I0, I1, I2) -> f2(I0, 0, I0) f2(I3, I4, I5) -> f3(I3, I4, I5) f3(I6, I7, I8) -> f1(I6, I7, I8) [1 + I7 <= I8] f3(I9, I10, I11) -> f4(I9, I10, I11) [I11 <= I10] f1(I12, I13, I14) -> f2(I12, I13, rnd3) [rnd3 = rnd3] f1(I15, I16, I17) -> f2(I15, rnd2, I17) [rnd2 = rnd2] The dependency graph for this problem is: 0 -> 1 1 -> 2 2 -> 3 3 -> 4, 5 4 -> 2 5 -> 2 Where: 0) f6#(x1, x2, x3) -> f5#(x1, x2, x3) 1) f5#(I0, I1, I2) -> f2#(I0, 0, I0) 2) f2#(I3, I4, I5) -> f3#(I3, I4, I5) 3) f3#(I6, I7, I8) -> f1#(I6, I7, I8) [1 + I7 <= I8] 4) f1#(I12, I13, I14) -> f2#(I12, I13, rnd3) [rnd3 = rnd3] 5) f1#(I15, I16, I17) -> f2#(I15, rnd2, I17) [rnd2 = rnd2] We have the following SCCs. { 2, 3, 4, 5 } DP problem for innermost termination. P = f2#(I3, I4, I5) -> f3#(I3, I4, I5) f3#(I6, I7, I8) -> f1#(I6, I7, I8) [1 + I7 <= I8] f1#(I12, I13, I14) -> f2#(I12, I13, rnd3) [rnd3 = rnd3] f1#(I15, I16, I17) -> f2#(I15, rnd2, I17) [rnd2 = rnd2] R = f6(x1, x2, x3) -> f5(x1, x2, x3) f5(I0, I1, I2) -> f2(I0, 0, I0) f2(I3, I4, I5) -> f3(I3, I4, I5) f3(I6, I7, I8) -> f1(I6, I7, I8) [1 + I7 <= I8] f3(I9, I10, I11) -> f4(I9, I10, I11) [I11 <= I10] f1(I12, I13, I14) -> f2(I12, I13, rnd3) [rnd3 = rnd3] f1(I15, I16, I17) -> f2(I15, rnd2, I17) [rnd2 = rnd2]
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