details

property	value
status	complete
benchmark	p-10.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n069.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	12.4553940296 seconds
cpu usage	12.799938754
max memory	2.752512E7

stage attributes

key	value
output-size	3565
starexec-result	MAYBE

output

/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1#(I0, I1, I2, I3, I4, I5, rnd7, rnd8, rnd9, rnd10) [rnd7 = rnd10 /\ rnd8 = rnd9 /\ rnd9 = rnd9 /\ rnd10 = rnd10] f3#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f1#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3#(I20, I21, I22, rnd4, rnd5, rnd6, I26, I27, I28, I29) [y1 = I21 /\ y2 = I22 /\ 0 <= -1 - y1 + y2 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ y3 = I21 /\ rnd6 = rnd6] R = f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1(I0, I1, I2, I3, I4, I5, rnd7, rnd8, rnd9, rnd10) [rnd7 = rnd10 /\ rnd8 = rnd9 /\ rnd9 = rnd9 /\ rnd10 = rnd10] f3(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f1(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) f1(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(I20, I21, I22, rnd4, rnd5, rnd6, I26, I27, I28, I29) [y1 = I21 /\ y2 = I22 /\ 0 <= -1 - y1 + y2 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ y3 = I21 /\ rnd6 = rnd6] f1(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2(rnd1, I31, I32, I40, I41, I35, I36, I37, I38, I39) [I42 = I31 /\ I43 = I32 /\ -1 * I42 + I43 <= 0 /\ I40 = I40 /\ I41 = I41 /\ rnd1 = rnd1] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 1) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1#(I0, I1, I2, I3, I4, I5, rnd7, rnd8, rnd9, rnd10) [rnd7 = rnd10 /\ rnd8 = rnd9 /\ rnd9 = rnd9 /\ rnd10 = rnd10] 2) f3#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f1#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) 3) f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3#(I20, I21, I22, rnd4, rnd5, rnd6, I26, I27, I28, I29) [y1 = I21 /\ y2 = I22 /\ 0 <= -1 - y1 + y2 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ y3 = I21 /\ rnd6 = rnd6] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f3#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f1#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) f1#(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3#(I20, I21, I22, rnd4, rnd5, rnd6, I26, I27, I28, I29) [y1 = I21 /\ y2 = I22 /\ 0 <= -1 - y1 + y2 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ y3 = I21 /\ rnd6 = rnd6] R = f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f4(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f1(I0, I1, I2, I3, I4, I5, rnd7, rnd8, rnd9, rnd10) [rnd7 = rnd10 /\ rnd8 = rnd9 /\ rnd9 = rnd9 /\ rnd10 = rnd10] f3(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f1(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) f1(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(I20, I21, I22, rnd4, rnd5, rnd6, I26, I27, I28, I29) [y1 = I21 /\ y2 = I22 /\ 0 <= -1 - y1 + y2 /\ rnd4 = rnd4 /\ rnd5 = rnd5 /\ y3 = I21 /\ rnd6 = rnd6] f1(I30, I31, I32, I33, I34, I35, I36, I37, I38, I39) -> f2(rnd1, I31, I32, I40, I41, I35, I36, I37, I38, I39) [I42 = I31 /\ I43 = I32 /\ -1 * I42 + I43 <= 0 /\ I40 = I40 /\ I41 = I41 /\ rnd1 = rnd1] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integ Trans Syste 27634