details

property	value
status	complete
benchmark	A05.itrs
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n028.star.cs.uiowa.edu
space	Mixed_ITRS_2014

run statistics

property	value
solver	Ctrl
configuration	Itrs
runtime (wallclock)	0.218461990356 seconds
cpu usage	0.225886885
max memory	9523200.0

stage attributes

key	value
output-size	1321
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_Itrs /export/starexec/sandbox2/benchmark/theBenchmark.itrs /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = min#(I2, I3) -> if#(I2 < I3, I2, I3) cond#(true, x, y) -> minus#(x, y + 1) minus#(I4, I5) -> cond#(min(I4, I5) = I5, I4, I5) minus#(I4, I5) -> min#(I4, I5) R = if(false, u, v) -> v if(true, I0, I1) -> I0 min(I2, I3) -> if(I2 < I3, I2, I3) cond(true, x, y) -> 1 + minus(x, y + 1) minus(I4, I5) -> cond(min(I4, I5) = I5, I4, I5) minus(I6, I6) -> 0 The dependency graph for this problem is: 0 -> 1 -> 2, 3 2 -> 1 3 -> 0 Where: 0) min#(I2, I3) -> if#(I2 < I3, I2, I3) 1) cond#(true, x, y) -> minus#(x, y + 1) 2) minus#(I4, I5) -> cond#(min(I4, I5) = I5, I4, I5) 3) minus#(I4, I5) -> min#(I4, I5) We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = cond#(true, x, y) -> minus#(x, y + 1) minus#(I4, I5) -> cond#(min(I4, I5) = I5, I4, I5) R = if(false, u, v) -> v if(true, I0, I1) -> I0 min(I2, I3) -> if(I2 < I3, I2, I3) cond(true, x, y) -> 1 + minus(x, y + 1) minus(I4, I5) -> cond(min(I4, I5) = I5, I4, I5) minus(I6, I6) -> 0 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integ TRS Inner 43557