details

property	value
status	complete
benchmark	NestedSingle.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n040.star.cs.uiowa.edu
space	POPL09

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.32888889313 seconds
cpu usage	5.067426583
max memory	2.6116096E8

stage attributes

key	value
output-size	20655
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). (0) CpxIntTrs (1) Koat Proof [FINISHED, 22 ms] (2) BOUNDS(1, n^1) (3) Loat Proof [FINISHED, 636 ms] (4) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: evalNestedSinglestart(A, B, C) -> Com_1(evalNestedSingleentryin(A, B, C)) :|: TRUE evalNestedSingleentryin(A, B, C) -> Com_1(evalNestedSinglebb5in(0, B, C)) :|: TRUE evalNestedSinglebb5in(A, B, C) -> Com_1(evalNestedSinglebb2in(A, B, A)) :|: B >= A + 1 evalNestedSinglebb5in(A, B, C) -> Com_1(evalNestedSinglereturnin(A, B, C)) :|: A >= B evalNestedSinglebb2in(A, B, C) -> Com_1(evalNestedSinglebb4in(A, B, C)) :|: C >= B evalNestedSinglebb2in(A, B, C) -> Com_1(evalNestedSinglebb3in(A, B, C)) :|: B >= C + 1 evalNestedSinglebb3in(A, B, C) -> Com_1(evalNestedSinglebb1in(A, B, C)) :|: 0 >= D + 1 evalNestedSinglebb3in(A, B, C) -> Com_1(evalNestedSinglebb1in(A, B, C)) :|: D >= 1 evalNestedSinglebb3in(A, B, C) -> Com_1(evalNestedSinglebb4in(A, B, C)) :|: TRUE evalNestedSinglebb1in(A, B, C) -> Com_1(evalNestedSinglebb2in(A, B, C + 1)) :|: TRUE evalNestedSinglebb4in(A, B, C) -> Com_1(evalNestedSinglebb5in(C + 1, B, C)) :|: TRUE evalNestedSinglereturnin(A, B, C) -> Com_1(evalNestedSinglestop(A, B, C)) :|: TRUE The start-symbols are:[evalNestedSinglestart_3] ---------------------------------------- (1) Koat Proof (FINISHED) YES(?, 24*ar_1 + 30) Initial complexity problem: 1: T: (Comp: ?, Cost: 1) evalNestedSinglestart(ar_0, ar_1, ar_2) -> Com_1(evalNestedSingleentryin(ar_0, ar_1, ar_2)) (Comp: ?, Cost: 1) evalNestedSingleentryin(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb5in(0, ar_1, ar_2)) (Comp: ?, Cost: 1) evalNestedSinglebb5in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb2in(ar_0, ar_1, ar_0)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalNestedSinglebb5in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglereturnin(ar_0, ar_1, ar_2)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalNestedSinglebb2in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb4in(ar_0, ar_1, ar_2)) [ ar_2 >= ar_1 ] (Comp: ?, Cost: 1) evalNestedSinglebb2in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb3in(ar_0, ar_1, ar_2)) [ ar_1 >= ar_2 + 1 ] (Comp: ?, Cost: 1) evalNestedSinglebb3in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb1in(ar_0, ar_1, ar_2)) [ 0 >= d + 1 ] (Comp: ?, Cost: 1) evalNestedSinglebb3in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb1in(ar_0, ar_1, ar_2)) [ d >= 1 ] (Comp: ?, Cost: 1) evalNestedSinglebb3in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb4in(ar_0, ar_1, ar_2)) (Comp: ?, Cost: 1) evalNestedSinglebb1in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb2in(ar_0, ar_1, ar_2 + 1)) (Comp: ?, Cost: 1) evalNestedSinglebb4in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb5in(ar_2 + 1, ar_1, ar_2)) (Comp: ?, Cost: 1) evalNestedSinglereturnin(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglestop(ar_0, ar_1, ar_2)) (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglestart(ar_0, ar_1, ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 1 produces the following problem: 2: T: (Comp: 1, Cost: 1) evalNestedSinglestart(ar_0, ar_1, ar_2) -> Com_1(evalNestedSingleentryin(ar_0, ar_1, ar_2)) (Comp: 1, Cost: 1) evalNestedSingleentryin(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb5in(0, ar_1, ar_2)) (Comp: ?, Cost: 1) evalNestedSinglebb5in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb2in(ar_0, ar_1, ar_0)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalNestedSinglebb5in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglereturnin(ar_0, ar_1, ar_2)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalNestedSinglebb2in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb4in(ar_0, ar_1, ar_2)) [ ar_2 >= ar_1 ] (Comp: ?, Cost: 1) evalNestedSinglebb2in(ar_0, ar_1, ar_2) -> Com_1(evalNestedSinglebb3in(ar_0, ar_1, ar_2)) [ ar_1 >= ar_2 + 1 ] popout

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actions

all output return to Compl Integ Trans Syste 26843