details

property	value
status	complete
benchmark	linear.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n054.star.cs.uiowa.edu
space	misc

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	1.75224900246 seconds
cpu usage	3.708440962
max memory	2.45346304E8

stage attributes

key	value
output-size	4158
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, max(102, 102 + Arg_0)). (0) CpxIntTrs (1) Koat2 Proof [FINISHED, 57 ms] (2) BOUNDS(1, max(102, 102 + Arg_0)) (3) Loat Proof [FINISHED, 133 ms] (4) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: start(A) -> Com_1(a(A)) :|: A >= 1 start(A) -> Com_1(a(100)) :|: A >= 100 && A <= 100 a(A) -> Com_1(a(A - 1)) :|: A >= 1 The start-symbols are:[start_1] ---------------------------------------- (1) Koat2 Proof (FINISHED) YES( ?, max([102, 102+Arg_0]) {O(n)}) Initial Complexity Problem: Start: start Program_Vars: Arg_0 Temp_Vars: Locations: a, start Transitions: a(Arg_0) -> a(Arg_0-1):|:1 <= Arg_0 start(Arg_0) -> a(Arg_0):|:1 <= Arg_0 start(Arg_0) -> a(100):|:Arg_0 <= 100 && 100 <= Arg_0 Timebounds: Overall timebound: max([102, 102+Arg_0]) {O(n)} 2: a->a: max([100, 100+Arg_0]) {O(n)} 0: start->a: 1 {O(1)} 1: start->a: 1 {O(1)} Costbounds: Overall costbound: max([102, 102+Arg_0]) {O(n)} 2: a->a: max([100, 100+Arg_0]) {O(n)} 0: start->a: 1 {O(1)} 1: start->a: 1 {O(1)} Sizebounds: `Lower: 2: a->a, Arg_0: 0 {O(1)} 0: start->a, Arg_0: 1 {O(1)} 1: start->a, Arg_0: 100 {O(1)} `Upper: 2: a->a, Arg_0: max([100, Arg_0]) {O(n)} 0: start->a, Arg_0: Arg_0 {O(n)} 1: start->a, Arg_0: 100 {O(1)} popout

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job log

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actions

all output return to Compl Integ Trans Syste 26843