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Compl Integ Trans Syste 26843 pair #381744272
details
property
value
status
complete
benchmark
Ex5.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n007.star.cs.uiowa.edu
space
PLDI10
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
2.32467603683 seconds
cpu usage
5.719568449
max memory
3.57654528E8
stage attributes
key
value
output-size
11149
starexec-result
WORST_CASE(NON_POLY, ?)
output
/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 618 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: evalEx5start(A, B, C, D, E) -> Com_1(evalEx5entryin(A, B, C, D, E)) :|: TRUE evalEx5entryin(A, B, C, D, E) -> Com_1(evalEx5bb6in(0, A, C, D, E)) :|: TRUE evalEx5bb6in(A, B, C, D, E) -> Com_1(evalEx5bb3in(A, B, 0, B, E)) :|: B >= A + 1 evalEx5bb6in(A, B, C, D, E) -> Com_1(evalEx5returnin(A, B, C, D, E)) :|: A >= B evalEx5bb3in(A, B, C, D, E) -> Com_1(evalEx5bb1in(A, B, C, D, E)) :|: 0 >= F + 1 evalEx5bb3in(A, B, C, D, E) -> Com_1(evalEx5bb1in(A, B, C, D, E)) :|: F >= 1 evalEx5bb3in(A, B, C, D, E) -> Com_1(evalEx5bb4in(A, B, C, D, E)) :|: TRUE evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb2in(A, B, C, D, D - 1)) :|: 0 >= F + 1 evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb2in(A, B, C, D, D - 1)) :|: 0 >= F + 1 && F >= 1 evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb2in(A, B, C, D, D - 1)) :|: F >= 1 evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb3in(A, B, C, D - 1, E)) :|: 0 >= 1 evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb2in(A, B, C, D, D)) :|: 0 >= 1 evalEx5bb1in(A, B, C, D, E) -> Com_1(evalEx5bb3in(A, B, C, D, E)) :|: TRUE evalEx5bb2in(A, B, C, D, E) -> Com_1(evalEx5bb3in(A, B, 1, E, E)) :|: TRUE evalEx5bb4in(A, B, C, D, E) -> Com_1(evalEx5bb6in(A + 1, D, C, D, E)) :|: C >= 0 && C <= 0 evalEx5bb4in(A, B, C, D, E) -> Com_1(evalEx5bb6in(A, D, C, D, E)) :|: 0 >= C + 1 evalEx5bb4in(A, B, C, D, E) -> Com_1(evalEx5bb6in(A, D, C, D, E)) :|: C >= 1 evalEx5returnin(A, B, C, D, E) -> Com_1(evalEx5stop(A, B, C, D, E)) :|: TRUE The start-symbols are:[evalEx5start_5] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: evalEx5start 0: evalEx5start -> evalEx5entryin : [], cost: 1 1: evalEx5entryin -> evalEx5bb6in : A'=0, B'=A, [], cost: 1 2: evalEx5bb6in -> evalEx5bb3in : C'=0, D'=B, [ B>=1+A ], cost: 1 3: evalEx5bb6in -> evalEx5returnin : [ A>=B ], cost: 1 4: evalEx5bb3in -> evalEx5bb1in : [ 0>=1+free ], cost: 1 5: evalEx5bb3in -> evalEx5bb1in : [ free_1>=1 ], cost: 1 6: evalEx5bb3in -> evalEx5bb4in : [], cost: 1 7: evalEx5bb1in -> evalEx5bb2in : E'=-1+D, [ 0>=1+free_2 ], cost: 1 8: evalEx5bb1in -> evalEx5bb2in : E'=-1+D, [ 0>=1+free_3 && free_3>=1 ], cost: 1 9: evalEx5bb1in -> evalEx5bb2in : E'=-1+D, [ free_4>=1 ], cost: 1 10: evalEx5bb1in -> evalEx5bb3in : D'=-1+D, [ 0>=1 ], cost: 1 11: evalEx5bb1in -> evalEx5bb2in : E'=D, [ 0>=1 ], cost: 1 12: evalEx5bb1in -> evalEx5bb3in : [], cost: 1 13: evalEx5bb2in -> evalEx5bb3in : C'=1, D'=E, [], cost: 1 14: evalEx5bb4in -> evalEx5bb6in : A'=1+A, B'=D, [ C==0 ], cost: 1 15: evalEx5bb4in -> evalEx5bb6in : B'=D, [ 0>=1+C ], cost: 1 16: evalEx5bb4in -> evalEx5bb6in : B'=D, [ C>=1 ], cost: 1 17: evalEx5returnin -> evalEx5stop : [], cost: 1 Removed unreachable and leaf rules: Start location: evalEx5start
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