details

property	value
status	complete
benchmark	SequentialSingle.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n003.star.cs.uiowa.edu
space	POPL09

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.12248206139 seconds
cpu usage	4.630337817
max memory	2.7615232E8

stage attributes

key	value
output-size	20659
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). (0) CpxIntTrs (1) Koat Proof [FINISHED, 10 ms] (2) BOUNDS(1, n^1) (3) Loat Proof [FINISHED, 520 ms] (4) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: evalSequentialSinglestart(A, B) -> Com_1(evalSequentialSingleentryin(A, B)) :|: TRUE evalSequentialSingleentryin(A, B) -> Com_1(evalSequentialSinglebb1in(0, B)) :|: TRUE evalSequentialSinglebb1in(A, B) -> Com_1(evalSequentialSinglebb5in(A, B)) :|: A >= B evalSequentialSinglebb1in(A, B) -> Com_1(evalSequentialSinglebb2in(A, B)) :|: B >= A + 1 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebbin(A, B)) :|: 0 >= C + 1 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebbin(A, B)) :|: C >= 1 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebb5in(A, B)) :|: TRUE evalSequentialSinglebbin(A, B) -> Com_1(evalSequentialSinglebb1in(A + 1, B)) :|: TRUE evalSequentialSinglebb5in(A, B) -> Com_1(evalSequentialSinglebb4in(A, B)) :|: B >= A + 1 evalSequentialSinglebb5in(A, B) -> Com_1(evalSequentialSinglereturnin(A, B)) :|: A >= B evalSequentialSinglebb4in(A, B) -> Com_1(evalSequentialSinglebb5in(A + 1, B)) :|: TRUE evalSequentialSinglereturnin(A, B) -> Com_1(evalSequentialSinglestop(A, B)) :|: TRUE The start-symbols are:[evalSequentialSinglestart_2] ---------------------------------------- (1) Koat Proof (FINISHED) YES(?, 7*ar_1 + 21) Initial complexity problem: 1: T: (Comp: ?, Cost: 1) evalSequentialSinglestart(ar_0, ar_1) -> Com_1(evalSequentialSingleentryin(ar_0, ar_1)) (Comp: ?, Cost: 1) evalSequentialSingleentryin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(0, ar_1)) (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ 0 >= c + 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ c >= 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) (Comp: ?, Cost: 1) evalSequentialSinglebbin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(ar_0 + 1, ar_1)) (Comp: ?, Cost: 1) evalSequentialSinglebb5in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb4in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb5in(ar_0, ar_1) -> Com_1(evalSequentialSinglereturnin(ar_0, ar_1)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb4in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0 + 1, ar_1)) (Comp: ?, Cost: 1) evalSequentialSinglereturnin(ar_0, ar_1) -> Com_1(evalSequentialSinglestop(ar_0, ar_1)) (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalSequentialSinglestart(ar_0, ar_1)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 1 produces the following problem: 2: T: (Comp: 1, Cost: 1) evalSequentialSinglestart(ar_0, ar_1) -> Com_1(evalSequentialSingleentryin(ar_0, ar_1)) (Comp: 1, Cost: 1) evalSequentialSingleentryin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(0, ar_1)) (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ 0 >= c + 1 ] (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ c >= 1 ] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Compl Integ Trans Syste 26843