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Compl Integ Trans Syste 26843 pair #381744349
details
property
value
status
complete
benchmark
aaron2.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n034.star.cs.uiowa.edu
space
WTC
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
4.90968513489 seconds
cpu usage
8.063807524
max memory
3.13831424E8
stage attributes
key
value
output-size
21941
starexec-result
WORST_CASE(Omega(n^1), O(n^1))
output
/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, max(10 + 5 * Arg_1 + -5 * Arg_2, 5) + nat(1 + 2 * Arg_1 + -2 * Arg_2)). (0) CpxIntTrs (1) Koat2 Proof [FINISHED, 1004 ms] (2) BOUNDS(1, max(10 + 5 * Arg_1 + -5 * Arg_2, 5) + nat(1 + 2 * Arg_1 + -2 * Arg_2)) (3) Loat Proof [FINISHED, 3211 ms] (4) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: evalaaron2start(A, B, C) -> Com_1(evalaaron2entryin(A, B, C)) :|: TRUE evalaaron2entryin(A, B, C) -> Com_1(evalaaron2bb6in(A, C, B)) :|: A >= 0 evalaaron2entryin(A, B, C) -> Com_1(evalaaron2returnin(A, B, C)) :|: 0 >= A + 1 evalaaron2bb6in(A, B, C) -> Com_1(evalaaron2returnin(A, B, C)) :|: B >= C + 1 evalaaron2bb6in(A, B, C) -> Com_1(evalaaron2returnin(A, B, C)) :|: 0 >= A + 1 evalaaron2bb6in(A, B, C) -> Com_1(evalaaron2bb3in(A, B, C)) :|: C >= B && A >= 0 evalaaron2bb3in(A, B, C) -> Com_1(evalaaron2bb4in(A, B, C)) :|: 0 >= D + 1 evalaaron2bb3in(A, B, C) -> Com_1(evalaaron2bb4in(A, B, C)) :|: D >= 1 evalaaron2bb3in(A, B, C) -> Com_1(evalaaron2bb5in(A, B, C)) :|: TRUE evalaaron2bb4in(A, B, C) -> Com_1(evalaaron2bb6in(A, B, C - A - 1)) :|: TRUE evalaaron2bb5in(A, B, C) -> Com_1(evalaaron2bb6in(A, B + A + 1, C)) :|: TRUE evalaaron2returnin(A, B, C) -> Com_1(evalaaron2stop(A, B, C)) :|: TRUE The start-symbols are:[evalaaron2start_3] ---------------------------------------- (1) Koat2 Proof (FINISHED) YES( ?, 5+2*2*max([0, 1+Arg_1-Arg_2])+max([0, 1+Arg_1-Arg_2])+max([0, 1+-2*Arg_2+2*Arg_1]) {O(n)}) Initial Complexity Problem: Start: evalaaron2start Program_Vars: Arg_0, Arg_1, Arg_2 Temp_Vars: D Locations: evalaaron2bb3in, evalaaron2bb4in, evalaaron2bb5in, evalaaron2bb6in, evalaaron2entryin, evalaaron2returnin, evalaaron2start, evalaaron2stop Transitions: evalaaron2bb3in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb4in(Arg_0,Arg_1,Arg_2):|:Arg_1 <= Arg_2 && 0 <= Arg_0 && D+1 <= 0 evalaaron2bb3in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb4in(Arg_0,Arg_1,Arg_2):|:Arg_1 <= Arg_2 && 0 <= Arg_0 && 1 <= D evalaaron2bb3in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb5in(Arg_0,Arg_1,Arg_2):|:Arg_1 <= Arg_2 && 0 <= Arg_0 evalaaron2bb4in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb6in(Arg_0,Arg_1,Arg_2-Arg_0-1):|:Arg_1 <= Arg_2 && 0 <= Arg_0 evalaaron2bb5in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb6in(Arg_0,Arg_1+Arg_0+1,Arg_2):|:Arg_1 <= Arg_2 && 0 <= Arg_0 evalaaron2bb6in(Arg_0,Arg_1,Arg_2) -> evalaaron2bb3in(Arg_0,Arg_1,Arg_2):|:0 <= Arg_0 && Arg_1 <= Arg_2 && 0 <= Arg_0 evalaaron2bb6in(Arg_0,Arg_1,Arg_2) -> evalaaron2returnin(Arg_0,Arg_1,Arg_2):|:0 <= Arg_0 && Arg_2+1 <= Arg_1 evalaaron2entryin(Arg_0,Arg_1,Arg_2) -> evalaaron2bb6in(Arg_0,Arg_2,Arg_1):|:0 <= Arg_0 evalaaron2entryin(Arg_0,Arg_1,Arg_2) -> evalaaron2returnin(Arg_0,Arg_1,Arg_2):|:Arg_0+1 <= 0 evalaaron2returnin(Arg_0,Arg_1,Arg_2) -> evalaaron2stop(Arg_0,Arg_1,Arg_2):|: evalaaron2start(Arg_0,Arg_1,Arg_2) -> evalaaron2entryin(Arg_0,Arg_1,Arg_2):|: Timebounds: Overall timebound: 5+2*2*max([0, 1+Arg_1-Arg_2])+max([0, 1+Arg_1-Arg_2])+max([0, 1+-2*Arg_2+2*Arg_1]) {O(n)} 6: evalaaron2bb3in->evalaaron2bb4in: max([0, 1+Arg_1-Arg_2]) {O(n)} 7: evalaaron2bb3in->evalaaron2bb4in: max([0, 1+Arg_1-Arg_2]) {O(n)} 8: evalaaron2bb3in->evalaaron2bb5in: max([0, 1+Arg_1-Arg_2]) {O(n)} 9: evalaaron2bb4in->evalaaron2bb6in: max([0, 1+-2*Arg_2+2*Arg_1]) {O(n)} 10: evalaaron2bb5in->evalaaron2bb6in: max([0, 1+Arg_1-Arg_2]) {O(n)} 3: evalaaron2bb6in->evalaaron2returnin: 1 {O(1)}
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