details

property	value
status	complete
benchmark	08.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n106.star.cs.uiowa.edu
space	Beerendonk

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	1.91885018349 seconds
cpu usage	4.010537215
max memory	2.2726656E8

stage attributes

key	value
output-size	4653
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, max(1, 1 + Arg_0)). (0) CpxIntTrs (1) Koat2 Proof [FINISHED, 38 ms] (2) BOUNDS(1, max(1, 1 + Arg_0)) (3) Loat Proof [FINISHED, 224 ms] (4) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: eval(A, B) -> Com_1(eval(A - 1, B - 1)) :|: A >= 1 && B >= 1 start(A, B) -> Com_1(eval(A, B)) :|: TRUE The start-symbols are:[start_2] ---------------------------------------- (1) Koat2 Proof (FINISHED) YES( ?, max([1, 1+Arg_0]) {O(n)}) Initial Complexity Problem: Start: start Program_Vars: Arg_0, Arg_1 Temp_Vars: Locations: eval, start Transitions: eval(Arg_0,Arg_1) -> eval(Arg_0-1,Arg_1-1):|:1 <= Arg_0 && 1 <= Arg_1 start(Arg_0,Arg_1) -> eval(Arg_0,Arg_1):|: Timebounds: Overall timebound: max([1, 1+Arg_0]) {O(n)} 0: eval->eval: max([0, Arg_0]) {O(n)} 1: start->eval: 1 {O(1)} Costbounds: Overall costbound: max([1, 1+Arg_0]) {O(n)} 0: eval->eval: max([0, Arg_0]) {O(n)} 1: start->eval: 1 {O(1)} Sizebounds: `Lower: 0: eval->eval, Arg_0: 0 {O(1)} 0: eval->eval, Arg_1: 0 {O(1)} 1: start->eval, Arg_0: Arg_0 {O(n)} 1: start->eval, Arg_1: Arg_1 {O(n)} `Upper: 0: eval->eval, Arg_0: Arg_0 {O(n)} 0: eval->eval, Arg_1: Arg_1 {O(n)} 1: start->eval, Arg_0: Arg_0 {O(n)} 1: start->eval, Arg_1: Arg_1 {O(n)} ---------------------------------------- popout

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job log

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actions

all output return to Compl Integ Trans Syste 26843