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Compl Integ Trans Syste 26843 pair #381744998
details
property
value
status
complete
benchmark
byron-1.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n042.star.cs.uiowa.edu
space
T2
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
1.82651805878 seconds
cpu usage
3.965440225
max memory
3.07228672E8
stage attributes
key
value
output-size
2567
starexec-result
WORST_CASE(?, O(n^1))
output
/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(?, O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, max(3, 3 + Arg_0)). (0) CpxIntTrs (1) Koat2 Proof [FINISHED, 236 ms] (2) BOUNDS(1, max(3, 3 + Arg_0)) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f2(A, B, C) -> Com_1(f2(-(B) + A, 1 + B, C)) :|: A >= 1 f3(A, B, C) -> Com_1(f2(A, B, C)) :|: B >= 1 f2(A, B, C) -> Com_1(f4(A, B, D)) :|: 0 >= A f3(A, B, C) -> Com_1(f4(A, B, D)) :|: 0 >= B The start-symbols are:[f3_3] ---------------------------------------- (1) Koat2 Proof (FINISHED) YES( ?, max([3, 3+Arg_0]) {O(n)}) Initial Complexity Problem: Start: f3 Program_Vars: Arg_0, Arg_1, Arg_2 Temp_Vars: D Locations: f2, f3, f4 Transitions: f2(Arg_0,Arg_1,Arg_2) -> f2(-Arg_1+Arg_0,1+Arg_1,Arg_2):|:1 <= Arg_1 && 1 <= Arg_0 f2(Arg_0,Arg_1,Arg_2) -> f4(Arg_0,Arg_1,D):|:1 <= Arg_1 && Arg_0 <= 0 f3(Arg_0,Arg_1,Arg_2) -> f2(Arg_0,Arg_1,Arg_2):|:1 <= Arg_1 f3(Arg_0,Arg_1,Arg_2) -> f4(Arg_0,Arg_1,D):|:Arg_1 <= 0 Timebounds: Overall timebound: max([3, 3+Arg_0]) {O(n)} 0: f2->f2: max([0, Arg_0]) {O(n)} 2: f2->f4: 1 {O(1)} 1: f3->f2: 1 {O(1)} 3: f3->f4: 1 {O(1)} Costbounds: Overall costbound: max([3, 3+Arg_0]) {O(n)} 0: f2->f2: max([0, Arg_0]) {O(n)} 2: f2->f4: 1 {O(1)} 1: f3->f2: 1 {O(1)} 3: f3->f4: 1 {O(1)} Sizebounds: `Lower: 0: f2->f2, Arg_1: 2 {O(1)} 0: f2->f2, Arg_2: Arg_2 {O(n)} 2: f2->f4, Arg_1: 1 {O(1)} 1: f3->f2, Arg_0: Arg_0 {O(n)}
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