details

property	value
status	complete
benchmark	ex31.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n020.star.cs.uiowa.edu
space	T2

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	1.87778615952 seconds
cpu usage	3.975072201
max memory	2.91954688E8

stage attributes

key	value
output-size	3591
starexec-result	WORST_CASE(NON_POLY, ?)

output

/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 316 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f0(A, B) -> Com_1(f4(0, 99)) :|: TRUE f4(A, B) -> Com_1(f4(E, B)) :|: B >= A + 1 && C >= D + 1 f4(A, B) -> Com_1(f4(A, E)) :|: B >= A + 1 f4(A, B) -> Com_1(f11(A, B)) :|: A >= B The start-symbols are:[f0_2] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: f0 0: f0 -> f4 : A'=0, B'=99, [], cost: 1 1: f4 -> f4 : A'=free_2, [ B>=1+A && free>=1+free_1 ], cost: 1 2: f4 -> f4 : B'=free_3, [ B>=1+A ], cost: 1 3: f4 -> f11 : [ A>=B ], cost: 1 Removed unreachable and leaf rules: Start location: f0 0: f0 -> f4 : A'=0, B'=99, [], cost: 1 1: f4 -> f4 : A'=free_2, [ B>=1+A && free>=1+free_1 ], cost: 1 2: f4 -> f4 : B'=free_3, [ B>=1+A ], cost: 1 Simplified all rules, resulting in: Start location: f0 0: f0 -> f4 : A'=0, B'=99, [], cost: 1 1: f4 -> f4 : A'=free_2, [ B>=1+A ], cost: 1 2: f4 -> f4 : B'=free_3, [ B>=1+A ], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 1: f4 -> f4 : A'=free_2, [ B>=1+A ], cost: 1 2: f4 -> f4 : B'=free_3, [ B>=1+A ], cost: 1 Accelerated rule 1 with NONTERM (after strengthening guard), yielding the new rule 4. Accelerated rule 2 with NONTERM (after strengthening guard), yielding the new rule 5. Removing the simple loops:. popout

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job log

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actions

all output return to Compl Integ Trans Syste 26843