details

property	value
status	complete
benchmark	ex11.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n075.star.cs.uiowa.edu
space	T2

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	3.41543388367 seconds
cpu usage	5.908622157
max memory	3.45591808E8

stage attributes

key	value
output-size	6360
starexec-result	WORST_CASE(NON_POLY, ?)

output

/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 1830 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f4(A, B) -> Com_1(f5(A, B)) :|: 0 >= A + 1 f4(A, B) -> Com_1(f5(A, B)) :|: A >= 1 f0(A, B) -> Com_1(f4(C, 0)) :|: TRUE f5(A, B) -> Com_1(f4(C, B + 1)) :|: 3 >= B f5(A, B) -> Com_1(f4(C, B + 1)) :|: B >= 5 f5(A, B) -> Com_1(f4(C, 1)) :|: B >= 4 && B <= 4 f4(A, B) -> Com_1(f12(0, B)) :|: A >= 0 && A <= 0 The start-symbols are:[f0_2] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: f0 0: f4 -> f5 : [ 0>=1+A ], cost: 1 1: f4 -> f5 : [ A>=1 ], cost: 1 6: f4 -> f12 : A'=0, [ A==0 ], cost: 1 2: f0 -> f4 : A'=free, B'=0, [], cost: 1 3: f5 -> f4 : A'=free_1, B'=1+B, [ 3>=B ], cost: 1 4: f5 -> f4 : A'=free_2, B'=1+B, [ B>=5 ], cost: 1 5: f5 -> f4 : A'=free_3, B'=1, [ B==4 ], cost: 1 Removed unreachable and leaf rules: Start location: f0 0: f4 -> f5 : [ 0>=1+A ], cost: 1 1: f4 -> f5 : [ A>=1 ], cost: 1 2: f0 -> f4 : A'=free, B'=0, [], cost: 1 3: f5 -> f4 : A'=free_1, B'=1+B, [ 3>=B ], cost: 1 4: f5 -> f4 : A'=free_2, B'=1+B, [ B>=5 ], cost: 1 5: f5 -> f4 : A'=free_3, B'=1, [ B==4 ], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on tree-shaped paths): Start location: f0 7: f4 -> f4 : A'=free_1, B'=1+B, [ 0>=1+A && 3>=B ], cost: 2 8: f4 -> f4 : A'=free_2, B'=1+B, [ 0>=1+A && B>=5 ], cost: 2 9: f4 -> f4 : A'=free_3, B'=1, [ 0>=1+A && B==4 ], cost: 2 10: f4 -> f4 : A'=free_1, B'=1+B, [ A>=1 && 3>=B ], cost: 2 11: f4 -> f4 : A'=free_2, B'=1+B, [ A>=1 && B>=5 ], cost: 2 12: f4 -> f4 : A'=free_3, B'=1, [ A>=1 && B==4 ], cost: 2 popout

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all output return to Compl Integ Trans Syste 26843