details

property	value
status	complete
benchmark	ex40.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n097.star.cs.uiowa.edu
space	T2

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.52624821663 seconds
cpu usage	3.996469388
max memory	2.92978688E8

stage attributes

key	value
output-size	3249
starexec-result	WORST_CASE(NON_POLY, ?)

output

/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 17 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f0(A, B) -> Com_1(f4(C, 0)) :|: TRUE f4(A, B) -> Com_1(f4(A, B + 1)) :|: 0 >= C + 1 f4(A, B) -> Com_1(f4(A, B + 1)) :|: TRUE f4(A, B) -> Com_1(f14(A, B)) :|: A >= 0 && B >= A + 1 f4(A, B) -> Com_1(f14(A, B)) :|: 0 >= A + 1 f4(A, B) -> Com_1(f14(A, B)) :|: A >= 0 && A >= B f4(A, B) -> Com_1(f14(A, B)) :|: 0 >= C + 1 && A >= 0 && B >= A + 1 The start-symbols are:[f0_2] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: f0 0: f0 -> f4 : A'=free, B'=0, [], cost: 1 1: f4 -> f4 : B'=1+B, [ 0>=1+free_1 ], cost: 1 2: f4 -> f4 : B'=1+B, [], cost: 1 3: f4 -> f14 : [ A>=0 && B>=1+A ], cost: 1 4: f4 -> f14 : [ 0>=1+A ], cost: 1 5: f4 -> f14 : [ A>=0 && A>=B ], cost: 1 6: f4 -> f14 : [ 0>=1+free_2 && A>=0 && B>=1+A ], cost: 1 Removed unreachable and leaf rules: Start location: f0 0: f0 -> f4 : A'=free, B'=0, [], cost: 1 1: f4 -> f4 : B'=1+B, [ 0>=1+free_1 ], cost: 1 2: f4 -> f4 : B'=1+B, [], cost: 1 Simplified all rules, resulting in: Start location: f0 0: f0 -> f4 : A'=free, B'=0, [], cost: 1 2: f4 -> f4 : B'=1+B, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 2: f4 -> f4 : B'=1+B, [], cost: 1 Accelerated rule 2 with NONTERM, yielding the new rule 7. Removing the simple loops: 2. popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Compl Integ Trans Syste 26843