details

property	value
status	complete
benchmark	speed_popl10_nested_single.c
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n003.star.cs.uiowa.edu
space	C4B_examples

run statistics

property	value
solver	AProVE
configuration	c_complexity
runtime (wallclock)	1.70606589317 seconds
cpu usage	2.858628676
max memory	2.73113088E8

stage attributes

key	value
output-size	28993
starexec-result	WORST_CASE(?, O(n^1))

output

/export/starexec/sandbox/solver/bin/starexec_run_c_complexity /export/starexec/sandbox/benchmark/theBenchmark.c /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(?, O(n^1)) proof of /export/starexec/sandbox/output/output_files/bench.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, n^1). (0) CpxIntTrs (1) Koat Proof [FINISHED, 481 ms] (2) BOUNDS(1, n^1) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: eval_speed_popl10_nested_single_start(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb0_in(v_3, v_n, v_x.0, v_x.1)) :|: TRUE eval_speed_popl10_nested_single_bb0_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb1_in(v_3, v_n, 0, v_x.1)) :|: TRUE eval_speed_popl10_nested_single_bb1_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb2_in(v_3, v_n, v_x.0, v_x.1)) :|: v_x.0 < v_n eval_speed_popl10_nested_single_bb1_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb6_in(v_3, v_n, v_x.0, v_x.1)) :|: v_x.0 >= v_n eval_speed_popl10_nested_single_bb2_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb3_in(v_3, v_n, v_x.0, v_x.0 + 1)) :|: TRUE eval_speed_popl10_nested_single_bb3_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb4_in(v_3, v_n, v_x.0, v_x.1)) :|: v_x.1 < v_n eval_speed_popl10_nested_single_bb3_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb1_in(v_3, v_n, v_x.1, v_x.1)) :|: v_x.1 >= v_n eval_speed_popl10_nested_single_bb4_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_2(v_3, v_n, v_x.0, v_x.1)) :|: TRUE eval_speed_popl10_nested_single_2(v_3, v_n, v_x.0, v_x.1) -> Com_2(eval_nondet_start(v_3, v_n, v_x.0, v_x.1), eval_speed_popl10_nested_single_3(nondef.0, v_n, v_x.0, v_x.1)) :|: TRUE eval_speed_popl10_nested_single_3(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb1_in(v_3, v_n, v_x.1, v_x.1)) :|: v_3 > 0 eval_speed_popl10_nested_single_3(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb5_in(v_3, v_n, v_x.0, v_x.1)) :|: v_3 <= 0 eval_speed_popl10_nested_single_bb5_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_bb3_in(v_3, v_n, v_x.0, v_x.1 + 1)) :|: TRUE eval_speed_popl10_nested_single_bb6_in(v_3, v_n, v_x.0, v_x.1) -> Com_1(eval_speed_popl10_nested_single_stop(v_3, v_n, v_x.0, v_x.1)) :|: TRUE The start-symbols are:[eval_speed_popl10_nested_single_start_4] ---------------------------------------- (1) Koat Proof (FINISHED) YES(?, 88*ar_1 + 6) Initial complexity problem: 1: T: (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglestart(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb0in(ar_0, ar_1, ar_2, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb0in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb1in(0, ar_1, ar_2, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb1in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb2in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb1in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb6in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ ar_0 >= ar_1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb2in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb3in(ar_0, ar_1, ar_0 + 1, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb3in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb4in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ ar_1 >= ar_2 + 1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb3in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb1in(ar_2, ar_1, ar_2, ar_3, ar_4)) [ ar_2 >= ar_1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb4in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsingle2(ar_0, ar_1, ar_2, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsingle20(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalnondetstart(ar_0, ar_1, ar_2, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsingle21(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsingle3(ar_0, ar_1, ar_2, ar_4, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsingle2(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_2(evalspeedpopl10nestedsingle20(ar_0, ar_1, ar_2, ar_3, f), evalspeedpopl10nestedsingle21(ar_0, ar_1, ar_2, ar_3, f)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsingle3(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb1in(ar_2, ar_1, ar_2, ar_3, ar_4)) [ ar_3 >= 1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsingle3(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb5in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ 0 >= ar_3 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb5in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb3in(ar_0, ar_1, ar_2 + 1, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb6in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglestop(ar_0, ar_1, ar_2, ar_3, ar_4)) (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglestart(ar_0, ar_1, ar_2, ar_3, ar_4)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 1 produces the following problem: 2: T: (Comp: 1, Cost: 1) evalspeedpopl10nestedsinglestart(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb0in(ar_0, ar_1, ar_2, ar_3, ar_4)) (Comp: 1, Cost: 1) evalspeedpopl10nestedsinglebb0in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb1in(0, ar_1, ar_2, ar_3, ar_4)) (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb1in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb2in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ ar_1 >= ar_0 + 1 ] (Comp: ?, Cost: 1) evalspeedpopl10nestedsinglebb1in(ar_0, ar_1, ar_2, ar_3, ar_4) -> Com_1(evalspeedpopl10nestedsinglebb6in(ar_0, ar_1, ar_2, ar_3, ar_4)) [ ar_0 >= ar_1 ] popout

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all output return to Compl C Integ Progr 85445