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Runti Compl Full Rewri 10127 pair #381902894
details
property
value
status
complete
benchmark
wst99.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n075.star.cs.uiowa.edu
space
Rubio_04
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
292.162242889 seconds
cpu usage
325.921516341
max memory
6.139363328E9
stage attributes
key
value
output-size
4518
starexec-result
WORST_CASE(Omega(n^1), ?)
output
/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). (0) CpxTRS (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (2) TRS for Loop Detection (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] (4) BEST (5) proven lower bound (6) LowerBoundPropagationProof [FINISHED, 0 ms] (7) BOUNDS(n^1, INF) (8) TRS for Loop Detection ---------------------------------------- (0) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: din(der(plus(X, Y))) -> u21(din(der(X)), X, Y) u21(dout(DX), X, Y) -> u22(din(der(Y)), X, Y, DX) u22(dout(DY), X, Y, DX) -> dout(plus(DX, DY)) din(der(times(X, Y))) -> u31(din(der(X)), X, Y) u31(dout(DX), X, Y) -> u32(din(der(Y)), X, Y, DX) u32(dout(DY), X, Y, DX) -> dout(plus(times(X, DY), times(Y, DX))) din(der(der(X))) -> u41(din(der(X)), X) u41(dout(DX), X) -> u42(din(der(DX)), X, DX) u42(dout(DDX), X, DX) -> dout(DDX) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) Transformed a relative TRS into a decreasing-loop problem. ---------------------------------------- (2) Obligation: Analyzing the following TRS for decreasing loops: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: din(der(plus(X, Y))) -> u21(din(der(X)), X, Y) u21(dout(DX), X, Y) -> u22(din(der(Y)), X, Y, DX) u22(dout(DY), X, Y, DX) -> dout(plus(DX, DY)) din(der(times(X, Y))) -> u31(din(der(X)), X, Y) u31(dout(DX), X, Y) -> u32(din(der(Y)), X, Y, DX) u32(dout(DY), X, Y, DX) -> dout(plus(times(X, DY), times(Y, DX))) din(der(der(X))) -> u41(din(der(X)), X) u41(dout(DX), X) -> u42(din(der(DX)), X, DX) u42(dout(DDX), X, DX) -> dout(DDX) S is empty. Rewrite Strategy: FULL ---------------------------------------- (3) DecreasingLoopProof (LOWER BOUND(ID)) The following loop(s) give(s) rise to the lower bound Omega(n^1): The rewrite sequence din(der(plus(X, Y))) ->^+ u21(din(der(X)), X, Y) gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. The pumping substitution is [X / plus(X, Y)]. The result substitution is [ ]. ---------------------------------------- (4) Complex Obligation (BEST) ---------------------------------------- (5) Obligation: Proved the lower bound n^1 for the following obligation:
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