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Runti Compl Inner Rewri 22807 pair #381904260
details
property
value
status
complete
benchmark
sat.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n077.star.cs.uiowa.edu
space
TCT_12
run statistics
property
value
solver
tct 2018-07-13
configuration
tct_rci
runtime (wallclock)
4.94766592979 seconds
cpu usage
21.48283284
max memory
1.29437696E8
stage attributes
key
value
output-size
95717
starexec-result
WORST_CASE(Omega(n^1),O(n^3))
output
/export/starexec/sandbox2/solver/bin/starexec_run_tct_rci /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1),O(n^3)) * Step 1: Sum WORST_CASE(Omega(n^1),O(n^3)) + Considered Problem: - Strict TRS: choice(cons(x,xs)) -> x choice(cons(x,xs)) -> choice(xs) eq(0(x),1(y)) -> false() eq(1(x),0(y)) -> false() eq(1(x),1(y)) -> eq(x,y) eq(O(x),0(y)) -> eq(x,y) eq(nil(),nil()) -> true() guess(cons(clause,cnf)) -> cons(choice(clause),guess(cnf)) guess(nil()) -> nil() if(false(),t,e) -> e if(true(),t,e) -> t member(x,cons(y,ys)) -> if(eq(x,y),true(),member(x,ys)) member(x,nil()) -> false() negate(0(x)) -> 1(x) negate(1(x)) -> 0(x) sat(cnf) -> satck(cnf,guess(cnf)) satck(cnf,assign) -> if(verify(assign),assign,unsat()) verify(cons(l,ls)) -> if(member(negate(l),ls),false(),verify(ls)) verify(nil()) -> true() - Signature: {choice/1,eq/2,guess/1,if/3,member/2,negate/1,sat/1,satck/2,verify/1} / {0/1,1/1,O/1,cons/2,false/0,nil/0 ,true/0,unsat/0} - Obligation: innermost runtime complexity wrt. defined symbols {choice,eq,guess,if,member,negate,sat,satck ,verify} and constructors {0,1,O,cons,false,nil,true,unsat} + Applied Processor: Sum {left = someStrategy, right = someStrategy} + Details: () ** Step 1.a:1: DecreasingLoops WORST_CASE(Omega(n^1),?) + Considered Problem: - Strict TRS: choice(cons(x,xs)) -> x choice(cons(x,xs)) -> choice(xs) eq(0(x),1(y)) -> false() eq(1(x),0(y)) -> false() eq(1(x),1(y)) -> eq(x,y) eq(O(x),0(y)) -> eq(x,y) eq(nil(),nil()) -> true() guess(cons(clause,cnf)) -> cons(choice(clause),guess(cnf)) guess(nil()) -> nil() if(false(),t,e) -> e if(true(),t,e) -> t member(x,cons(y,ys)) -> if(eq(x,y),true(),member(x,ys)) member(x,nil()) -> false() negate(0(x)) -> 1(x) negate(1(x)) -> 0(x) sat(cnf) -> satck(cnf,guess(cnf)) satck(cnf,assign) -> if(verify(assign),assign,unsat()) verify(cons(l,ls)) -> if(member(negate(l),ls),false(),verify(ls)) verify(nil()) -> true() - Signature: {choice/1,eq/2,guess/1,if/3,member/2,negate/1,sat/1,satck/2,verify/1} / {0/1,1/1,O/1,cons/2,false/0,nil/0 ,true/0,unsat/0} - Obligation: innermost runtime complexity wrt. defined symbols {choice,eq,guess,if,member,negate,sat,satck ,verify} and constructors {0,1,O,cons,false,nil,true,unsat} + Applied Processor: DecreasingLoops {bound = AnyLoop, narrow = 10} + Details: The system has following decreasing Loops: choice(y){y -> cons(x,y)} = choice(cons(x,y)) ->^+ choice(y) = C[choice(y) = choice(y){}] ** Step 1.b:1: DependencyPairs WORST_CASE(?,O(n^3)) + Considered Problem: - Strict TRS: choice(cons(x,xs)) -> x choice(cons(x,xs)) -> choice(xs) eq(0(x),1(y)) -> false() eq(1(x),0(y)) -> false() eq(1(x),1(y)) -> eq(x,y) eq(O(x),0(y)) -> eq(x,y) eq(nil(),nil()) -> true() guess(cons(clause,cnf)) -> cons(choice(clause),guess(cnf)) guess(nil()) -> nil() if(false(),t,e) -> e if(true(),t,e) -> t member(x,cons(y,ys)) -> if(eq(x,y),true(),member(x,ys)) member(x,nil()) -> false() negate(0(x)) -> 1(x) negate(1(x)) -> 0(x) sat(cnf) -> satck(cnf,guess(cnf)) satck(cnf,assign) -> if(verify(assign),assign,unsat()) verify(cons(l,ls)) -> if(member(negate(l),ls),false(),verify(ls)) verify(nil()) -> true() - Signature: {choice/1,eq/2,guess/1,if/3,member/2,negate/1,sat/1,satck/2,verify/1} / {0/1,1/1,O/1,cons/2,false/0,nil/0 ,true/0,unsat/0}
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