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Runti Compl Inner Rewri 22807 pair #381904856
details
property
value
status
complete
benchmark
ExAppendixB_AEL03_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n029.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
292.219900131 seconds
cpu usage
1152.80819221
max memory
1.508540416E10
stage attributes
key
value
output-size
9150
starexec-result
WORST_CASE(Omega(n^1), ?)
output
/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), ?) proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). (0) CpxTRS (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (2) TRS for Loop Detection (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] (4) BEST (5) proven lower bound (6) LowerBoundPropagationProof [FINISHED, 0 ms] (7) BOUNDS(n^1, INF) (8) TRS for Loop Detection ---------------------------------------- (0) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: a__from(X) -> cons(mark(X), from(s(X))) a__2ndspos(0, Z) -> rnil a__2ndspos(s(N), cons(X, Z)) -> a__2ndspos(s(mark(N)), cons2(X, mark(Z))) a__2ndspos(s(N), cons2(X, cons(Y, Z))) -> rcons(posrecip(mark(Y)), a__2ndsneg(mark(N), mark(Z))) a__2ndsneg(0, Z) -> rnil a__2ndsneg(s(N), cons(X, Z)) -> a__2ndsneg(s(mark(N)), cons2(X, mark(Z))) a__2ndsneg(s(N), cons2(X, cons(Y, Z))) -> rcons(negrecip(mark(Y)), a__2ndspos(mark(N), mark(Z))) a__pi(X) -> a__2ndspos(mark(X), a__from(0)) a__plus(0, Y) -> mark(Y) a__plus(s(X), Y) -> s(a__plus(mark(X), mark(Y))) a__times(0, Y) -> 0 a__times(s(X), Y) -> a__plus(mark(Y), a__times(mark(X), mark(Y))) a__square(X) -> a__times(mark(X), mark(X)) mark(from(X)) -> a__from(mark(X)) mark(2ndspos(X1, X2)) -> a__2ndspos(mark(X1), mark(X2)) mark(2ndsneg(X1, X2)) -> a__2ndsneg(mark(X1), mark(X2)) mark(pi(X)) -> a__pi(mark(X)) mark(plus(X1, X2)) -> a__plus(mark(X1), mark(X2)) mark(times(X1, X2)) -> a__times(mark(X1), mark(X2)) mark(square(X)) -> a__square(mark(X)) mark(0) -> 0 mark(s(X)) -> s(mark(X)) mark(posrecip(X)) -> posrecip(mark(X)) mark(negrecip(X)) -> negrecip(mark(X)) mark(nil) -> nil mark(cons(X1, X2)) -> cons(mark(X1), X2) mark(cons2(X1, X2)) -> cons2(X1, mark(X2)) mark(rnil) -> rnil mark(rcons(X1, X2)) -> rcons(mark(X1), mark(X2)) a__from(X) -> from(X) a__2ndspos(X1, X2) -> 2ndspos(X1, X2) a__2ndsneg(X1, X2) -> 2ndsneg(X1, X2) a__pi(X) -> pi(X) a__plus(X1, X2) -> plus(X1, X2) a__times(X1, X2) -> times(X1, X2) a__square(X) -> square(X) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) Transformed a relative TRS into a decreasing-loop problem. ---------------------------------------- (2) Obligation: Analyzing the following TRS for decreasing loops: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: a__from(X) -> cons(mark(X), from(s(X))) a__2ndspos(0, Z) -> rnil a__2ndspos(s(N), cons(X, Z)) -> a__2ndspos(s(mark(N)), cons2(X, mark(Z))) a__2ndspos(s(N), cons2(X, cons(Y, Z))) -> rcons(posrecip(mark(Y)), a__2ndsneg(mark(N), mark(Z))) a__2ndsneg(0, Z) -> rnil a__2ndsneg(s(N), cons(X, Z)) -> a__2ndsneg(s(mark(N)), cons2(X, mark(Z))) a__2ndsneg(s(N), cons2(X, cons(Y, Z))) -> rcons(negrecip(mark(Y)), a__2ndspos(mark(N), mark(Z))) a__pi(X) -> a__2ndspos(mark(X), a__from(0)) a__plus(0, Y) -> mark(Y) a__plus(s(X), Y) -> s(a__plus(mark(X), mark(Y))) a__times(0, Y) -> 0 a__times(s(X), Y) -> a__plus(mark(Y), a__times(mark(X), mark(Y))) a__square(X) -> a__times(mark(X), mark(X))
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