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TRS Outer 67415 pair #381918061
details
property
value
status
complete
benchmark
test9.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n041.star.cs.uiowa.edu
space
Strategy_outermost_added_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.35300779343 seconds
cpu usage
3.24468422
max memory
2.14597632E8
stage attributes
key
value
output-size
1744
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 117 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: f(0, 1, X) -> h(X, X) h(0, X) -> f(0, X, X) g(X, Y) -> X g(X, Y) -> Y Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: f(0, 1, X) -> h(X, X) h(0, X) -> f(0, X, X) g(X, Y) -> X g(X, Y) -> Y Outermost Strategy. ---------- Loop: ---------- h(g(1, 0), g(1, 0)) -> h(0, g(1, 0)) with rule g(X, Y') -> Y' at position [0] and matcher [X / 1, Y' / 0] h(0, g(1, 0)) -> f(0, g(1, 0), g(1, 0)) with rule h(0, X) -> f(0, X, X) at position [] and matcher [X / g(1, 0)] f(0, g(1, 0), g(1, 0)) -> f(0, 1, g(1, 0)) with rule g(X', Y) -> X' at position [1] and matcher [X' / 1, Y / 0] f(0, 1, g(1, 0)) -> h(g(1, 0), g(1, 0)) with rule f(0, 1, X) -> h(X, X) at position [] and matcher [X / g(1, 0)] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO
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