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TRS Outer 67415 pair #381918139
details
property
value
status
complete
benchmark
jwno6.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n026.star.cs.uiowa.edu
space
Strategy_outermost_added_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.21953511238 seconds
cpu usage
2.738484809
max memory
1.88452864E8
stage attributes
key
value
output-size
2087
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: f(x, h(y)) -> h(f(f(h(a), y), x)) Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: f(x, h(y)) -> h(f(f(h(a), y), x)) Outermost Strategy. ---------- Loop: ---------- f(f(h(y'''), f(x''', h(y'))), f(h(y''), f(x'', h(y)))) -> f(f(h(y'''), f(x''', h(y'))), f(h(y''), h(f(f(h(a), y), x'')))) with rule f(x'''', h(y1)) -> h(f(f(h(a), y1), x'''')) at position [1,1] and matcher [x'''' / x'', y1 / y] f(f(h(y'''), f(x''', h(y'))), f(h(y''), h(f(f(h(a), y), x'')))) -> f(f(h(y'''), f(x''', h(y'))), h(f(f(h(a), f(f(h(a), y), x'')), h(y'')))) with rule f(x', h(y'1)) -> h(f(f(h(a), y'1), x')) at position [1] and matcher [x' / h(y''), y'1 / f(f(h(a), y), x'')] f(f(h(y'''), f(x''', h(y'))), h(f(f(h(a), f(f(h(a), y), x'')), h(y'')))) -> h(f(f(h(a), f(f(h(a), f(f(h(a), y), x'')), h(y''))), f(h(y'''), f(x''', h(y'))))) with rule f(x, h(y1)) -> h(f(f(h(a), y1), x)) at position [] and matcher [x / f(h(y'''), f(x''', h(y'))), y1 / f(f(h(a), f(f(h(a), y), x'')), h(y''))] Now an instance of the first term with Matcher [y / y', y' / y'', y'' / y''', x'' / x''', y''' / a, x''' / f(h(a), f(f(h(a), y), x''))] occurs in the last term at position [0]. Context: h([]) We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO
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