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TRS Outer 67415 pair #381918177
details
property
value
status
complete
benchmark
Ex14_AEGL02_Z.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n051.star.cs.uiowa.edu
space
Strategy_outermost_added_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.48608708382 seconds
cpu usage
3.837544385
max memory
2.66067968E8
stage attributes
key
value
output-size
2819
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 208 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: from(X) -> cons(X, n__from(s(X))) length(n__nil) -> 0 length(n__cons(X, Y)) -> s(length1(activate(Y))) length1(X) -> length(activate(X)) from(X) -> n__from(X) nil -> n__nil cons(X1, X2) -> n__cons(X1, X2) activate(n__from(X)) -> from(X) activate(n__nil) -> nil activate(n__cons(X1, X2)) -> cons(X1, X2) activate(X) -> X Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: from(X) -> cons(X, n__from(s(X))) length(n__nil) -> 0 length(n__cons(X, Y)) -> s(length1(activate(Y))) length1(X) -> length(activate(X)) from(X) -> n__from(X) nil -> n__nil cons(X1, X2) -> n__cons(X1, X2) activate(n__from(X)) -> from(X) activate(n__nil) -> nil activate(n__cons(X1, X2)) -> cons(X1, X2) activate(X) -> X Outermost Strategy. ---------- Loop: ---------- length1(activate(n__from(X'))) -> length(activate(activate(n__from(X')))) with rule length1(X) -> length(activate(X)) at position [] and matcher [X / activate(n__from(X'))] length(activate(activate(n__from(X')))) -> length(activate(n__from(X'))) with rule activate(X) -> X at position [0] and matcher [X / activate(n__from(X'))] length(activate(n__from(X'))) -> length(from(X')) with rule activate(n__from(X'')) -> from(X'') at position [0] and matcher [X'' / X'] length(from(X')) -> length(cons(X', n__from(s(X')))) with rule from(X) -> cons(X, n__from(s(X))) at position [0] and matcher [X / X'] length(cons(X', n__from(s(X')))) -> length(n__cons(X', n__from(s(X')))) with rule cons(X1, X2) -> n__cons(X1, X2) at position [0] and matcher [X1 / X', X2 / n__from(s(X'))] length(n__cons(X', n__from(s(X')))) -> s(length1(activate(n__from(s(X'))))) with rule length(n__cons(X, Y)) -> s(length1(activate(Y))) at position [] and matcher [X / X', Y / n__from(s(X'))] Now an instance of the first term with Matcher [X' / s(X')] occurs in the last term at position [0]. Context: s([]) We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO
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