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TRS Outer 67415 pair #381918257
details
property
value
status
complete
benchmark
cime4.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n072.star.cs.uiowa.edu
space
Strategy_outermost_added_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.92269206047 seconds
cpu usage
3.056539802
max memory
2.44224E8
stage attributes
key
value
output-size
2172
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 34 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: g(X) -> u(h(X), h(X), X) u(d, c(Y), X) -> k(Y) h(d) -> c(a) h(d) -> c(b) f(k(a), k(b), X) -> f(X, X, X) Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: g(X) -> u(h(X), h(X), X) u(d, c(Y), X) -> k(Y) h(d) -> c(a) h(d) -> c(b) f(k(a), k(b), X) -> f(X, X, X) Outermost Strategy. ---------- Loop: ---------- f(u(d, h(d), X'), u(d, h(d), X'), u(d, h(d), X')) -> f(u(d, h(d), X'), u(d, c(b), X'), u(d, h(d), X')) with rule h(d) -> c(b) at position [1,1] and matcher [ ] f(u(d, h(d), X'), u(d, c(b), X'), u(d, h(d), X')) -> f(u(d, h(d), X'), k(b), u(d, h(d), X')) with rule u(d, c(Y), X'') -> k(Y) at position [1] and matcher [Y / b, X'' / X'] f(u(d, h(d), X'), k(b), u(d, h(d), X')) -> f(u(d, c(a), X'), k(b), u(d, h(d), X')) with rule h(d) -> c(a) at position [0,1] and matcher [ ] f(u(d, c(a), X'), k(b), u(d, h(d), X')) -> f(k(a), k(b), u(d, h(d), X')) with rule u(d, c(Y), X'') -> k(Y) at position [0] and matcher [Y / a, X'' / X'] f(k(a), k(b), u(d, h(d), X')) -> f(u(d, h(d), X'), u(d, h(d), X'), u(d, h(d), X')) with rule f(k(a), k(b), X) -> f(X, X, X) at position [] and matcher [X / u(d, h(d), X')] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO
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