details

property	value
status	complete
benchmark	lambda2.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n053.star.cs.uiowa.edu
space	Mixed_HO_10

run statistics

property	value
solver	sol 37957
configuration	hrs
runtime (wallclock)	0.355145931244 seconds
cpu usage	0.43279099
max memory	8.1063936E7

stage attributes

key	value
output-size	2356
starexec-result	NO

output

/export/starexec/sandbox2/solver/bin/starexec_run_hrs /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO We split firstr-order part and higher-order part, and do modular checking by a general modularity. ******** FO SN check ******** Check non-SN using NTI (Non-Termination Inference by Payet) ******** Computation rules ******** (1) fapp(lam(X),Y) => subst(X,Y) (2) subst(v,Y) => Y (3) subst(lam(X),Y) => lam(X) (4) subst(fapp(X,Z),Y) => fapp(subst(X,Y),subst(Z,Y)) backward process killed -- 26 rule(s) generated forward+backward process killed -- 10 rule(s) generated NO let R be the TRS under consideration subst(fapp(_1,_2),_3) -> fapp(subst(_1,_3),subst(_2,_3)) is in elim_R(R) let r0 be the right-hand side of this rule p0 = 0 is a position in r0 we have r0|p0 = subst(_1,_3) subst(v,_4) -> _4 is in R let l'0 be the left-hand side of this rule theta0 = {_1/v, _3/_4} is a mgu of r0|p0 and l'0 ==> subst(fapp(v,_1),_2) -> fapp(_2,subst(_1,_2)) is in EU_R^1 let r1 be the right-hand side of this rule p1 = 1 is a position in r1 we have r1|p1 = subst(_1,_2) subst(v,_3) -> _3 is in R let l'1 be the left-hand side of this rule theta1 = {_1/v, _2/_3} is a mgu of r1|p1 and l'1 ==> subst(fapp(v,v),_1) -> fapp(_1,_1) is in EU_R^2 let r2 be the right-hand side of this rule p2 = epsilon is a position in r2 we have r2|p2 = fapp(_1,_1) fapp(lam(_2),_3) -> subst(_2,_3) is in R let l'2 be the left-hand side of this rule theta2 = {_1/lam(_2), _3/lam(_2)} is a mgu of r2|p2 and l'2 ==> subst(fapp(v,v),lam(_1)) -> subst(_1,lam(_1)) is in EU_R^3 let l be the left-hand side and r be the right-hand side of this rule let p = epsilon let theta = {_1/fapp(v,v)} let theta' = {} we have r|p = subst(_1,lam(_1)) and theta'(theta(l)) = theta(r|p) so, theta(l) = subst(fapp(v,v),lam(fapp(v,v))) is non-terminating w.r.t. R Termination disproved by the forward process proof stopped at iteration i=3, depth k=2 9 rule(s) generated >>NO ******** Signature ******** fapp : (o,o) -> o lam : o -> o v : o subst : (o,o) -> o ******** Computation Rules ******** (1) fapp(lam(X),Y) => subst(X,Y) (2) subst(v,Y) => Y (3) subst(lam(X),Y) => lam(X) (4) subst(fapp(X,Z),Y) => fapp(subst(X,Y),subst(Z,Y)) NO popout

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all output return to HRS 58631