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Java Bytec 64199 pair #381919316
details
property
value
status
complete
benchmark
sum_rec.jar
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n054.star.cs.uiowa.edu
space
Julia_12_recursive
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.23622202873 seconds
cpu usage
5.844153808
max memory
5.1040256E8
stage attributes
key
value
output-size
2230
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.jar /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.jar # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty termination of the given Bare JBC problem could be disproven: (0) Bare JBC problem (1) BareJBCToJBCProof [EQUIVALENT, 96 ms] (2) JBC problem (3) JBCNonTerm [COMPLETE, 197 ms] (4) NO ---------------------------------------- (0) Obligation: need to prove termination of the following program: public class Sum { public static int sum(int n) { if (n == 0) return 0; else return n + sum(n - 1); } public static void main(String args[]) { sum(-1); } } ---------------------------------------- (1) BareJBCToJBCProof (EQUIVALENT) initialized classpath ---------------------------------------- (2) Obligation: need to prove termination of the following program: public class Sum { public static int sum(int n) { if (n == 0) return 0; else return n + sum(n - 1); } public static void main(String args[]) { sum(-1); } } ---------------------------------------- (3) JBCNonTerm (COMPLETE) Reached a loop using the following run: 0:<Sum.main||0: push -1|| - || -> YES: (JL1) 1:<Sum.main||1: Sum.sum(I)I|| - ||-1> YES: (JL1) 2:<Sum.sum||0: load INT #0||#0: -1|| -> YES: (JL1) Start state of loop: [i10(lv_0_0)] <Sum.sum||0: load INT #0||#0: i11|| -> i10: # i11: # YES: (JL1) In the loop head node, references [i11, i10] were interesting. All methods calls in the loop body are side-effect free, hence they can be ignored. By SMT, we could prove (T and (((path1_i11 = path1_i12 and path1_i14 = (path1_i12 - 1) and path1_i14 = res_i10 and path1_i14 = res_i11 and path1_i10 = initial_i10 and path1_i11 = initial_i11) and path1_i12 < 0) and ((res1_i11 = res1_i12 and res1_i14 = (res1_i12 - 1) and res_i10 = res1_i10 and res_i11 = res1_i11) and !res1_i12 < 0))) to be UNSAT. Consequently, the loop will not terminate. ---------------------------------------- (4) NO
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