Logic Progr 19030 pair #381919750

details

property	value
status	complete
benchmark	shapes.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n075.star.cs.uiowa.edu
space	lpexamples

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.43220686913 seconds
cpu usage	10.30122439
max memory	9.55437056E8

stage attributes

key	value
output-size	158330
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.pl /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES
proof of /export/starexec/sandbox2/benchmark/theBenchmark.pl
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Left Termination of the query pattern

shapes(g,a)

w.r.t. the given Prolog program could successfully be proven:

(0) Prolog
(1) PrologToDTProblemTransformerProof [SOUND, 19 ms]
(2) TRIPLES
(3) TriplesToPiDPProof [SOUND, 0 ms]
(4) PiDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) AND
    (7) PiDP
        (8) UsableRulesProof [EQUIVALENT, 0 ms]
        (9) PiDP
        (10) PiDPToQDPProof [SOUND, 0 ms]
        (11) QDP
        (12) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (13) YES
    (14) PiDP
        (15) UsableRulesProof [EQUIVALENT, 0 ms]
        (16) PiDP
        (17) PiDPToQDPProof [SOUND, 0 ms]
        (18) QDP
        (19) QDPQMonotonicMRRProof [EQUIVALENT, 62 ms]
        (20) QDP
        (21) DependencyGraphProof [EQUIVALENT, 0 ms]
        (22) TRUE
    (23) PiDP
        (24) UsableRulesProof [EQUIVALENT, 0 ms]
        (25) PiDP
        (26) PiDPToQDPProof [SOUND, 0 ms]
        (27) QDP
        (28) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (29) YES
    (30) PiDP
        (31) UsableRulesProof [EQUIVALENT, 0 ms]
        (32) PiDP
        (33) PiDPToQDPProof [SOUND, 0 ms]
        (34) QDP
        (35) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (36) YES


----------------------------------------

(0)
Obligation:
Clauses:

shapes(Matrix, N) :- ','(varmat(Matrix, MatrixWithVars), unif_matrx(MatrixWithVars)).
varmat([], []).
varmat(.(L, Ls), .(VL, VLs)) :- ','(varmat(L, VL), varmat(Ls, VLs)).
varmat(.(black, Xs), .(black, VXs)) :- varmat(Xs, VXs).
varmat(.(white, Xs), .(w(X1), VXs)) :- varmat(Xs, VXs).
unif_matrx(.(L1, .(L2, Ls))) :- ','(unif_lines(L1, L2), unif_matrx(.(L2, Ls))).
unif_matrx(.(X2, [])).
unif_lines(.(W, .(X, L1s)), .(Y, .(Z, L2s))) :- ','(unif_pairs(.(W, .(X, .(Y, .(Z, .(W, .(Y, .(X, .(Z, .(W, .(Z, .(X, .(Y, []))))))))))))), unif_lines(.(X, L1s), .(Z, L2s))).
unif_lines(.(X3, []), .(X4, [])).
unif_pairs([]).
unif_pairs(.(A, .(B, Pairs))) :- ','(unif(A, B), unif_pairs(Pairs)).
unif(w(A), w(A)).
unif(black, black).
unif(black, w(X5)).
unif(w(X6), black).


Query: shapes(g,a)
----------------------------------------

(1) PrologToDTProblemTransformerProof (SOUND)
Built DT problem from termination graph DT10.

{
    "root": 3,
    "program": {
        "directives": [],
        "clauses": [
            [
                "(shapes Matrix N)",
                "(',' (varmat Matrix MatrixWithVars) (unif_matrx MatrixWithVars))"
            ],
            [
                "(varmat ([]) ([]))",
                null
            ],
            [
                "(varmat (. L Ls) (. VL VLs))",

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