details

property	value
status	complete
benchmark	palindrome.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n040.star.cs.uiowa.edu
space	BCGGV05

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.72679591179 seconds
cpu usage	4.015149418
max memory	2.92958208E8

stage attributes

key	value
output-size	10571
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.pl /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.pl # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Left Termination of the query pattern palindrome(g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 1 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: palindrome(Xs) :- reverse(Xs, Xs). reverse(X1s, X2s) :- reverse(X1s, [], X2s). reverse([], Xs, Xs). reverse(.(X, X1s), X2s, Ys) :- reverse(X1s, .(X, X2s), Ys). Query: palindrome(g) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: palindrome_in_1: (b) reverse_in_2: (b,b) reverse_in_3: (b,b,b) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: palindrome_in_g(Xs) -> U1_g(Xs, reverse_in_gg(Xs, Xs)) reverse_in_gg(X1s, X2s) -> U2_gg(X1s, X2s, reverse_in_ggg(X1s, [], X2s)) reverse_in_ggg([], Xs, Xs) -> reverse_out_ggg([], Xs, Xs) reverse_in_ggg(.(X, X1s), X2s, Ys) -> U3_ggg(X, X1s, X2s, Ys, reverse_in_ggg(X1s, .(X, X2s), Ys)) U3_ggg(X, X1s, X2s, Ys, reverse_out_ggg(X1s, .(X, X2s), Ys)) -> reverse_out_ggg(.(X, X1s), X2s, Ys) U2_gg(X1s, X2s, reverse_out_ggg(X1s, [], X2s)) -> reverse_out_gg(X1s, X2s) U1_g(Xs, reverse_out_gg(Xs, Xs)) -> palindrome_out_g(Xs) The argument filtering Pi contains the following mapping: palindrome_in_g(x1) = palindrome_in_g(x1) U1_g(x1, x2) = U1_g(x2) reverse_in_gg(x1, x2) = reverse_in_gg(x1, x2) U2_gg(x1, x2, x3) = U2_gg(x3) reverse_in_ggg(x1, x2, x3) = reverse_in_ggg(x1, x2, x3) [] = [] reverse_out_ggg(x1, x2, x3) = reverse_out_ggg .(x1, x2) = .(x1, x2) U3_ggg(x1, x2, x3, x4, x5) = U3_ggg(x5) reverse_out_gg(x1, x2) = reverse_out_gg palindrome_out_g(x1) = palindrome_out_g Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog popout

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