Logic Progr 19030 pair #381920103

details

property	value
status	complete
benchmark	inorder-bf.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n038.star.cs.uiowa.edu
space	BCGGV05

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.88520812988 seconds
cpu usage	4.48711695
max memory	3.69344512E8

stage attributes

key	value
output-size	16482
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.pl /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES
proof of /export/starexec/sandbox2/benchmark/theBenchmark.pl
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Left Termination of the query pattern

in_order(g,a)

w.r.t. the given Prolog program could successfully be proven:

(0) Prolog
(1) PrologToPiTRSProof [SOUND, 0 ms]
(2) PiTRS
(3) DependencyPairsProof [EQUIVALENT, 0 ms]
(4) PiDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) AND
    (7) PiDP
        (8) UsableRulesProof [EQUIVALENT, 0 ms]
        (9) PiDP
        (10) PiDPToQDPProof [SOUND, 0 ms]
        (11) QDP
        (12) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (13) YES
    (14) PiDP
        (15) PiDPToQDPProof [SOUND, 0 ms]
        (16) QDP
        (17) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (18) YES


----------------------------------------

(0)
Obligation:
Clauses:

in_order(void, []).
in_order(tree(X, Left, Right), Xs) :- ','(in_order(Left, Ls), ','(in_order(Right, Rs), app(Ls, .(X, Rs), Xs))).
app([], X, X).
app(.(X, Xs), Ys, .(X, Zs)) :- app(Xs, Ys, Zs).


Query: in_order(g,a)
----------------------------------------

(1) PrologToPiTRSProof (SOUND)
We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes:

in_order_in_2: (b,f)

app_in_3: (b,b,f)

Transforming Prolog into the following Term Rewriting System:

Pi-finite rewrite system:
The TRS R consists of the following rules:

   in_order_in_ga(void, []) -> in_order_out_ga(void, [])
   in_order_in_ga(tree(X, Left, Right), Xs) -> U1_ga(X, Left, Right, Xs, in_order_in_ga(Left, Ls))
   U1_ga(X, Left, Right, Xs, in_order_out_ga(Left, Ls)) -> U2_ga(X, Left, Right, Xs, Ls, in_order_in_ga(Right, Rs))
   U2_ga(X, Left, Right, Xs, Ls, in_order_out_ga(Right, Rs)) -> U3_ga(X, Left, Right, Xs, app_in_gga(Ls, .(X, Rs), Xs))
   app_in_gga([], X, X) -> app_out_gga([], X, X)
   app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U4_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs))
   U4_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs))
   U3_ga(X, Left, Right, Xs, app_out_gga(Ls, .(X, Rs), Xs)) -> in_order_out_ga(tree(X, Left, Right), Xs)

The argument filtering Pi contains the following mapping:
in_order_in_ga(x1, x2)  =  in_order_in_ga(x1)

void  =  void

in_order_out_ga(x1, x2)  =  in_order_out_ga(x2)

tree(x1, x2, x3)  =  tree(x1, x2, x3)

U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x1, x3, x5)

U2_ga(x1, x2, x3, x4, x5, x6)  =  U2_ga(x1, x5, x6)

U3_ga(x1, x2, x3, x4, x5)  =  U3_ga(x5)

app_in_gga(x1, x2, x3)  =  app_in_gga(x1, x2)

[]  =  []

app_out_gga(x1, x2, x3)  =  app_out_gga(x3)

.(x1, x2)  =  .(x1, x2)

U4_gga(x1, x2, x3, x4, x5)  =  U4_gga(x1, x5)

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