details

property	value
status	complete
benchmark	assoc.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n069.star.cs.uiowa.edu
space	Mixed_relative_TRS

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.86754 seconds
cpu usage	4.33338
user time	4.16567
system time	0.167705
max virtual memory	1.8612456E7
max residence set size	295304.0

stage attributes

key	value
starexec-result	NO

output

4.15/1.79 NO 4.25/1.83 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 4.25/1.83 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.25/1.83 4.25/1.83 4.25/1.83 Termination of the given RelTRS could be disproven: 4.25/1.83 4.25/1.83 (0) RelTRS 4.25/1.83 (1) RelTRSLoopFinderProof [COMPLETE, 44 ms] 4.25/1.83 (2) NO 4.25/1.83 4.25/1.83 4.25/1.83 ---------------------------------------- 4.25/1.83 4.25/1.83 (0) 4.25/1.83 Obligation: 4.25/1.83 Relative term rewrite system: 4.25/1.83 The relative TRS consists of the following R rules: 4.25/1.83 4.25/1.83 f(a, x) -> f(x, f(b, x)) 4.25/1.83 4.25/1.83 The relative TRS consists of the following S rules: 4.25/1.83 4.25/1.83 f(f(x, y), z) -> f(x, f(y, z)) 4.25/1.83 f(x, f(y, z)) -> f(f(x, y), z) 4.25/1.83 4.25/1.83 4.25/1.83 ---------------------------------------- 4.25/1.83 4.25/1.83 (1) RelTRSLoopFinderProof (COMPLETE) 4.25/1.83 The following loop was found: 4.25/1.83 4.25/1.83 ---------- Loop: ---------- 4.25/1.83 4.25/1.83 f(a, f(x', f(y', a))) -> f(a, f(f(x', y'), a)) with rule f(x'', f(y'', z)) -> f(f(x'', y''), z) at position [1] and matcher [x'' / x', y'' / y', z / a] 4.25/1.83 4.25/1.83 f(a, f(f(x', y'), a)) -> f(f(f(x', y'), a), f(b, f(f(x', y'), a))) with rule f(a, x) -> f(x, f(b, x)) at position [] and matcher [x / f(f(x', y'), a)] 4.25/1.83 4.25/1.83 f(f(f(x', y'), a), f(b, f(f(x', y'), a))) -> f(f(x', y'), f(a, f(b, f(f(x', y'), a)))) with rule f(f(x, y), z) -> f(x, f(y, z)) at position [] and matcher [x / f(x', y'), y / a, z / f(b, f(f(x', y'), a))] 4.25/1.83 4.25/1.83 Now an instance of the first term with Matcher [x' / b, y' / f(x', y')] occurs in the last term at position [1]. 4.25/1.83 4.25/1.83 Context: f(f(x', y'), []) 4.25/1.83 4.25/1.83 Therefore, the relative TRS problem does not terminate. 4.25/1.83 ---------------------------------------- 4.25/1.83 4.25/1.83 (2) 4.25/1.83 NO 4.28/1.86 EOF popout

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all output return to TRS_Relative 2019-03-21 03.54