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TRS_Relative 2019-03-21 03.54 pair #429988727
details
property
value
status
complete
benchmark
rt1-3.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n001.star.cs.uiowa.edu
space
Relative_05
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
1.47677 seconds
cpu usage
4.66904
user time
3.69835
system time
0.970685
max virtual memory
3896428.0
max residence set size
69128.0
stage attributes
key
value
starexec-result
YES
output
4.47/1.46 YES 4.47/1.47 4.47/1.47 Problem: 4.47/1.47 strict: 4.47/1.47 t(f(x),g(y),f(z)) -> t(z,g(x),g(y)) 4.47/1.47 t(g(x),g(y),f(z)) -> t(f(y),f(z),x) 4.47/1.47 weak: 4.47/1.47 f(g(x)) -> g(f(x)) 4.47/1.47 g(f(x)) -> f(g(x)) 4.47/1.47 f(f(x)) -> g(g(x)) 4.47/1.47 g(g(x)) -> f(f(x)) 4.47/1.47 4.47/1.47 Proof: 4.47/1.47 Matrix Interpretation Processor: dim=2 4.47/1.47 4.47/1.47 interpretation: 4.47/1.47 [1 0] [1 0] [1 0] 4.47/1.47 [t](x0, x1, x2) = [1 0]x0 + [1 0]x1 + [1 0]x2, 4.47/1.47 4.47/1.47 [1 0] [1] 4.47/1.47 [g](x0) = [0 0]x0 + [0], 4.47/1.47 4.47/1.47 [1 0] [1] 4.47/1.47 [f](x0) = [0 0]x0 + [0] 4.47/1.47 orientation: 4.47/1.47 [1 0] [1 0] [1 0] [3] [1 0] [1 0] [1 0] [2] 4.47/1.47 t(f(x),g(y),f(z)) = [1 0]x + [1 0]y + [1 0]z + [3] >= [1 0]x + [1 0]y + [1 0]z + [2] = t(z,g(x),g(y)) 4.47/1.47 4.47/1.47 [1 0] [1 0] [1 0] [3] [1 0] [1 0] [1 0] [2] 4.47/1.47 t(g(x),g(y),f(z)) = [1 0]x + [1 0]y + [1 0]z + [3] >= [1 0]x + [1 0]y + [1 0]z + [2] = t(f(y),f(z),x) 4.47/1.47 4.47/1.47 [1 0] [2] [1 0] [2] 4.47/1.47 f(g(x)) = [0 0]x + [0] >= [0 0]x + [0] = g(f(x)) 4.47/1.47 4.47/1.47 [1 0] [2] [1 0] [2] 4.47/1.47 g(f(x)) = [0 0]x + [0] >= [0 0]x + [0] = f(g(x)) 4.47/1.47 4.47/1.47 [1 0] [2] [1 0] [2] 4.47/1.47 f(f(x)) = [0 0]x + [0] >= [0 0]x + [0] = g(g(x)) 4.47/1.47 4.47/1.47 [1 0] [2] [1 0] [2] 4.47/1.47 g(g(x)) = [0 0]x + [0] >= [0 0]x + [0] = f(f(x)) 4.47/1.47 problem: 4.47/1.47 strict: 4.47/1.47 4.47/1.47 weak: 4.47/1.47 f(g(x)) -> g(f(x)) 4.47/1.47 g(f(x)) -> f(g(x)) 4.47/1.47 f(f(x)) -> g(g(x)) 4.47/1.47 g(g(x)) -> f(f(x)) 4.47/1.47 Qed 4.47/1.47 EOF
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