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Complexity_C_Integer 2019-03-21 04.38 pair #429988966
details
property
value
status
complete
benchmark
GulavaniGulwani-CAV2008-Fig1c_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n054.star.cs.uiowa.edu
space
Adapted_from_Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c_complexity
runtime (wallclock)
1.67859 seconds
cpu usage
2.18781
user time
2.02249
system time
0.165315
max virtual memory
1.8273644E7
max residence set size
182248.0
stage attributes
key
value
starexec-result
WORST_CASE(?, O(n^1))
output
2.06/1.64 WORST_CASE(?, O(n^1)) 2.06/1.65 proof of /export/starexec/sandbox/output/output_files/bench.koat 2.06/1.65 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.06/1.65 2.06/1.65 2.06/1.65 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, n^1). 2.06/1.65 2.06/1.65 (0) CpxIntTrs 2.06/1.65 (1) Koat Proof [FINISHED, 82 ms] 2.06/1.65 (2) BOUNDS(1, n^1) 2.06/1.65 2.06/1.65 2.06/1.65 ---------------------------------------- 2.06/1.65 2.06/1.65 (0) 2.06/1.65 Obligation: 2.06/1.65 Complexity Int TRS consisting of the following rules: 2.06/1.65 eval_foo_start(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_bb0_in(v_.0, v_i, v_n, v_x)) :|: TRUE 2.06/1.65 eval_foo_bb0_in(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_bb1_in(v_x, v_i, v_n, v_x)) :|: TRUE 2.06/1.65 eval_foo_bb1_in(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_bb2_in(v_.0, v_i, v_n, v_x)) :|: v_.0 < v_n 2.06/1.65 eval_foo_bb1_in(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_bb3_in(v_.0, v_i, v_n, v_x)) :|: v_.0 >= v_n 2.06/1.65 eval_foo_bb2_in(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_bb1_in(v_.0 + 1, v_i, v_n, v_x)) :|: TRUE 2.06/1.65 eval_foo_bb3_in(v_.0, v_i, v_n, v_x) -> Com_1(eval_foo_stop(v_.0, v_i, v_n, v_x)) :|: TRUE 2.06/1.65 2.06/1.65 The start-symbols are:[eval_foo_start_4] 2.06/1.65 2.06/1.65 2.06/1.65 ---------------------------------------- 2.06/1.65 2.06/1.65 (1) Koat Proof (FINISHED) 2.06/1.65 YES(?, 2*ar_1 + 2*ar_2 + 8) 2.06/1.65 2.06/1.65 2.06/1.65 2.06/1.65 Initial complexity problem: 2.06/1.65 2.06/1.65 1: T: 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoostart(ar_0, ar_1, ar_2) -> Com_1(evalfoobb0in(ar_0, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb0in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb1in(ar_1, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb2in(ar_0, ar_1, ar_2)) [ ar_2 >= ar_0 + 1 ] 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb3in(ar_0, ar_1, ar_2)) [ ar_0 >= ar_2 ] 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb1in(ar_0 + 1, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb3in(ar_0, ar_1, ar_2) -> Com_1(evalfoostop(ar_0, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(evalfoostart(ar_0, ar_1, ar_2)) [ 0 <= 0 ] 2.06/1.65 2.06/1.65 start location: koat_start 2.06/1.65 2.06/1.65 leaf cost: 0 2.06/1.65 2.06/1.65 2.06/1.65 2.06/1.65 Repeatedly propagating knowledge in problem 1 produces the following problem: 2.06/1.65 2.06/1.65 2: T: 2.06/1.65 2.06/1.65 (Comp: 1, Cost: 1) evalfoostart(ar_0, ar_1, ar_2) -> Com_1(evalfoobb0in(ar_0, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb1in(ar_1, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb2in(ar_0, ar_1, ar_2)) [ ar_2 >= ar_0 + 1 ] 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb3in(ar_0, ar_1, ar_2)) [ ar_0 >= ar_2 ] 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1, ar_2) -> Com_1(evalfoobb1in(ar_0 + 1, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: ?, Cost: 1) evalfoobb3in(ar_0, ar_1, ar_2) -> Com_1(evalfoostop(ar_0, ar_1, ar_2)) 2.06/1.65 2.06/1.65 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(evalfoostart(ar_0, ar_1, ar_2)) [ 0 <= 0 ] 2.06/1.65 2.06/1.65 start location: koat_start 2.06/1.65 2.06/1.65 leaf cost: 0 2.06/1.65 2.06/1.65 2.06/1.65 2.06/1.65 A polynomial rank function with 2.06/1.65 2.06/1.65 Pol(evalfoostart) = 2 2.06/1.65 2.06/1.65 Pol(evalfoobb0in) = 2 2.06/1.65 2.06/1.65 Pol(evalfoobb1in) = 2 2.06/1.65 2.06/1.65 Pol(evalfoobb2in) = 2 2.06/1.65 2.06/1.65 Pol(evalfoobb3in) = 1 2.06/1.65 2.06/1.65 Pol(evalfoostop) = 0 2.06/1.65 2.06/1.65 Pol(koat_start) = 2 2.06/1.65 2.06/1.65 orients all transitions weakly and the transitions 2.06/1.65
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