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Complexity_ITS 2019-03-21 04.46 pair #429989814
details
property
value
status
complete
benchmark
speed_popl10_sequential_single.c.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n115.star.cs.uiowa.edu
space
Flores-Montoya_16
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
2.40916 seconds
cpu usage
5.03991
user time
4.74347
system time
0.296436
max virtual memory
1.85254E7
max residence set size
220164.0
stage attributes
key
value
starexec-result
WORST_CASE(Omega(n^1), O(n^1))
output
4.82/2.37 WORST_CASE(Omega(n^1), O(n^1)) 5.00/2.38 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 5.00/2.38 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 5.00/2.38 5.00/2.38 5.00/2.38 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 5.00/2.38 5.00/2.38 (0) CpxIntTrs 5.00/2.38 (1) Koat Proof [FINISHED, 129 ms] 5.00/2.38 (2) BOUNDS(1, n^1) 5.00/2.38 (3) Loat Proof [FINISHED, 629 ms] 5.00/2.38 (4) BOUNDS(n^1, INF) 5.00/2.38 5.00/2.38 5.00/2.38 ---------------------------------------- 5.00/2.38 5.00/2.38 (0) 5.00/2.38 Obligation: 5.00/2.38 Complexity Int TRS consisting of the following rules: 5.00/2.38 eval_start_start(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb0_in(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_bb0_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_0(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_0(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_1(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_1(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_2(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_2(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_3(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_3(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb1_in(v_1, v_n, 0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_bb1_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb2_in(v_1, v_n, v_x_0, v_x_1)) :|: v_x_0 < v_n 5.00/2.38 eval_start_bb1_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb4_in(v_1, v_n, v_x_0, v_x_0)) :|: v_x_0 >= v_n 5.00/2.38 eval_start_bb2_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_4(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_4(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_5(nondef_0, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 eval_start_5(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb4_in(v_1, v_n, v_x_0, v_x_0)) :|: v_1 > 0 5.00/2.38 eval_start_5(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb3_in(v_1, v_n, v_x_0, v_x_1)) :|: v_1 <= 0 5.00/2.38 eval_start_bb3_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb1_in(v_1, v_n, v_x_0 + 1, v_x_1)) :|: TRUE 5.00/2.38 eval_start_bb4_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb5_in(v_1, v_n, v_x_0, v_x_1)) :|: v_x_1 < v_n 5.00/2.38 eval_start_bb4_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb6_in(v_1, v_n, v_x_0, v_x_1)) :|: v_x_1 >= v_n 5.00/2.38 eval_start_bb5_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_bb4_in(v_1, v_n, v_x_0, v_x_1 + 1)) :|: TRUE 5.00/2.38 eval_start_bb6_in(v_1, v_n, v_x_0, v_x_1) -> Com_1(eval_start_stop(v_1, v_n, v_x_0, v_x_1)) :|: TRUE 5.00/2.38 5.00/2.38 The start-symbols are:[eval_start_start_4] 5.00/2.38 5.00/2.38 5.00/2.38 ---------------------------------------- 5.00/2.38 5.00/2.38 (1) Koat Proof (FINISHED) 5.00/2.38 YES(?, 7*ar_1 + 32) 5.00/2.38 5.00/2.38 5.00/2.38 5.00/2.38 Initial complexity problem: 5.00/2.38 5.00/2.38 1: T: 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartstart(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb0in(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb0in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart0(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart0(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart1(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart1(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart2(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart2(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart3(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart3(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb1in(0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb1in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb2in(ar_0, ar_1, ar_2, ar_3)) [ ar_1 >= ar_0 + 1 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb1in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb4in(ar_0, ar_1, ar_0, ar_3)) [ ar_0 >= ar_1 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb2in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart4(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart4(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart5(ar_0, ar_1, ar_2, e)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart5(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb4in(ar_0, ar_1, ar_0, ar_3)) [ ar_3 >= 1 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstart5(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb3in(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_3 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb3in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb1in(ar_0 + 1, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb4in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb5in(ar_0, ar_1, ar_2, ar_3)) [ ar_1 >= ar_2 + 1 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb4in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb6in(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_1 ] 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb5in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb4in(ar_0, ar_1, ar_2 + 1, ar_3)) 5.00/2.38 5.00/2.38 (Comp: ?, Cost: 1) evalstartbb6in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartstop(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartstart(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 5.00/2.38 5.00/2.38 start location: koat_start 5.00/2.38 5.00/2.38 leaf cost: 0 5.00/2.38 5.00/2.38 5.00/2.38 5.00/2.38 Repeatedly propagating knowledge in problem 1 produces the following problem: 5.00/2.38 5.00/2.38 2: T: 5.00/2.38 5.00/2.38 (Comp: 1, Cost: 1) evalstartstart(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstartbb0in(ar_0, ar_1, ar_2, ar_3)) 5.00/2.38 5.00/2.38 (Comp: 1, Cost: 1) evalstartbb0in(ar_0, ar_1, ar_2, ar_3) -> Com_1(evalstart0(ar_0, ar_1, ar_2, ar_3))
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