Complexity_ITS 2019-03-21 04.46 pair #429990300

details

property	value
status	complete
benchmark	st88.bug.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n058.star.cs.uiowa.edu
space	T2

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.96705 seconds
cpu usage	6.79159
user time	6.41681
system time	0.374777
max virtual memory	1.8755148E7
max residence set size	214196.0

stage attributes

key	value
starexec-result	WORST_CASE(NON_POLY, ?)

output

6.69/2.93	WORST_CASE(NON_POLY, ?)
6.69/2.94	proof of /export/starexec/sandbox/benchmark/theBenchmark.koat
6.69/2.94	# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty
6.69/2.94	
6.69/2.94	
6.69/2.94	The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF).
6.69/2.94	
6.69/2.94	(0) CpxIntTrs
6.69/2.94	(1) Loat Proof [FINISHED, 1330 ms]
6.69/2.94	(2) BOUNDS(INF, INF)
6.69/2.94	
6.69/2.94	
6.69/2.94	----------------------------------------
6.69/2.94	
6.69/2.94	(0)
6.69/2.94	Obligation:
6.69/2.94	Complexity Int TRS consisting of the following rules:
6.69/2.94	f26(A, B) -> Com_1(f2(A, B)) :|: TRUE
6.69/2.94	f2(A, B) -> Com_1(f2(A, B)) :|: TRUE
6.69/2.94	f9(A, B) -> Com_1(f12(A, C)) :|: 5 >= A && 0 >= C + 1
6.69/2.94	f9(A, B) -> Com_1(f12(A, C)) :|: 5 >= A && C >= 1
6.69/2.94	f12(A, B) -> Com_1(f9(A + 1, B)) :|: A >= 6
6.69/2.94	f28(A, B) -> Com_1(f30(A, B)) :|: TRUE
6.69/2.94	f20(A, B) -> Com_1(f20(A - 1, B)) :|: A >= 3
6.69/2.94	f20(A, B) -> Com_1(f9(A, B)) :|: 2 >= A
6.69/2.94	f12(A, B) -> Com_1(f9(A + 1, B)) :|: 5 >= A
6.69/2.94	f9(A, B) -> Com_1(f20(A, 0)) :|: 5 >= A
6.69/2.94	f9(A, B) -> Com_1(f20(A, B)) :|: A >= 6
6.69/2.94	f0(A, B) -> Com_1(f9(C, B)) :|: TRUE
6.69/2.94	
6.69/2.94	The start-symbols are:[f0_2]
6.69/2.94	
6.69/2.94	
6.69/2.94	----------------------------------------
6.69/2.94	
6.69/2.94	(1) Loat Proof (FINISHED)
6.69/2.94	
6.69/2.94	
6.69/2.94	### Pre-processing the ITS problem ###
6.69/2.94	
6.69/2.94	
6.69/2.94	
6.69/2.94	Initial linear ITS problem
6.69/2.94	
6.69/2.94	   Start location: f0
6.69/2.94	
6.69/2.94	      0: f26 -> f2 : [], cost: 1
6.69/2.94	
6.69/2.94	      1: f2 -> f2 : [], cost: 1
6.69/2.94	
6.69/2.94	      2: f9 -> f12 : B'=free, [ 5>=A && 0>=1+free ], cost: 1
6.69/2.94	
6.69/2.94	      3: f9 -> f12 : B'=free_1, [ 5>=A && free_1>=1 ], cost: 1
6.69/2.94	
6.69/2.94	      9: f9 -> f20 : B'=0, [ 5>=A ], cost: 1
6.69/2.94	
6.69/2.94	     10: f9 -> f20 : [ A>=6 ], cost: 1
6.69/2.94	
6.69/2.94	      4: f12 -> f9 : A'=1+A, [ A>=6 ], cost: 1
6.69/2.94	
6.69/2.94	      8: f12 -> f9 : A'=1+A, [ 5>=A ], cost: 1
6.69/2.94	
6.69/2.94	      5: f28 -> f30 : [], cost: 1
6.69/2.94	
6.69/2.94	      6: f20 -> f20 : A'=-1+A, [ A>=3 ], cost: 1
6.69/2.94	
6.69/2.94	      7: f20 -> f9 : [ 2>=A ], cost: 1
6.69/2.94	
6.69/2.94	     11: f0 -> f9 : A'=free_2, [], cost: 1
6.69/2.94	
6.69/2.94	
6.69/2.94	
6.69/2.94	Removed unreachable and leaf rules:
6.69/2.94	
6.69/2.94	   Start location: f0
6.69/2.94	
6.69/2.94	      2: f9 -> f12 : B'=free, [ 5>=A && 0>=1+free ], cost: 1
6.69/2.94	
6.69/2.94	      3: f9 -> f12 : B'=free_1, [ 5>=A && free_1>=1 ], cost: 1
6.69/2.94	
6.69/2.94	      9: f9 -> f20 : B'=0, [ 5>=A ], cost: 1
6.69/2.94	
6.69/2.94	     10: f9 -> f20 : [ A>=6 ], cost: 1
6.69/2.94	
6.69/2.94	      4: f12 -> f9 : A'=1+A, [ A>=6 ], cost: 1
6.69/2.94	
6.69/2.94	      8: f12 -> f9 : A'=1+A, [ 5>=A ], cost: 1
6.69/2.94	
6.69/2.94	      6: f20 -> f20 : A'=-1+A, [ A>=3 ], cost: 1
6.69/2.94	
6.69/2.94	      7: f20 -> f9 : [ 2>=A ], cost: 1
6.69/2.94	
6.69/2.94	     11: f0 -> f9 : A'=free_2, [], cost: 1
6.69/2.94	
6.69/2.94	
6.69/2.94	
6.69/2.94	### Simplification by acceleration and chaining ###
6.69/2.94	
6.69/2.94	
6.69/2.94

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