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Complexity_ITS 2019-03-21 04.46 pair #429990738
details
property
value
status
complete
benchmark
p-44.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n007.star.cs.uiowa.edu
space
T2
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
1.90676 seconds
cpu usage
3.96376
user time
3.69628
system time
0.267477
max virtual memory
1.8525884E7
max residence set size
215824.0
stage attributes
key
value
starexec-result
WORST_CASE(Omega(n^1), O(n^1))
output
3.74/1.87 WORST_CASE(Omega(n^1), O(n^1)) 3.74/1.88 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 3.74/1.88 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.74/1.88 3.74/1.88 3.74/1.88 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 3.74/1.88 3.74/1.88 (0) CpxIntTrs 3.74/1.88 (1) Koat Proof [FINISHED, 26 ms] 3.74/1.88 (2) BOUNDS(1, n^1) 3.74/1.88 (3) Loat Proof [FINISHED, 220 ms] 3.74/1.88 (4) BOUNDS(n^1, INF) 3.74/1.88 3.74/1.88 3.74/1.88 ---------------------------------------- 3.74/1.88 3.74/1.88 (0) 3.74/1.88 Obligation: 3.74/1.88 Complexity Int TRS consisting of the following rules: 3.74/1.88 f300(A, B, C) -> Com_1(f300(-(1) + A, -(2) + A, C)) :|: A >= 1 && B + A >= 1 && B >= 1 3.74/1.88 f300(A, B, C) -> Com_1(f1(A, B, D)) :|: A >= 1 && 0 >= B + A && B >= 1 3.74/1.88 f300(A, B, C) -> Com_1(f1(A, B, D)) :|: B >= 1 && 0 >= A 3.74/1.88 f300(A, B, C) -> Com_1(f1(A, B, D)) :|: 0 >= B 3.74/1.88 f2(A, B, C) -> Com_1(f300(A, B, C)) :|: TRUE 3.74/1.88 3.74/1.88 The start-symbols are:[f2_3] 3.74/1.88 3.74/1.88 3.74/1.88 ---------------------------------------- 3.74/1.88 3.74/1.88 (1) Koat Proof (FINISHED) 3.74/1.88 YES(?, ar_0 + 3) 3.74/1.88 3.74/1.88 3.74/1.88 3.74/1.88 Initial complexity problem: 3.74/1.88 3.74/1.88 1: T: 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0 - 1, ar_0 - 2, ar_2)) [ ar_0 >= 1 /\ ar_1 + ar_0 >= 1 /\ ar_1 >= 1 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ ar_0 >= 1 /\ 0 >= ar_1 + ar_0 /\ ar_1 >= 1 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ ar_1 >= 1 /\ 0 >= ar_0 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ 0 >= ar_1 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f2(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0, ar_1, ar_2)) 3.74/1.88 3.74/1.88 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(f2(ar_0, ar_1, ar_2)) [ 0 <= 0 ] 3.74/1.88 3.74/1.88 start location: koat_start 3.74/1.88 3.74/1.88 leaf cost: 0 3.74/1.88 3.74/1.88 3.74/1.88 3.74/1.88 Testing for reachability in the complexity graph removes the following transition from problem 1: 3.74/1.88 3.74/1.88 f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ ar_0 >= 1 /\ 0 >= ar_1 + ar_0 /\ ar_1 >= 1 ] 3.74/1.88 3.74/1.88 We thus obtain the following problem: 3.74/1.88 3.74/1.88 2: T: 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ 0 >= ar_1 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ ar_1 >= 1 /\ 0 >= ar_0 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0 - 1, ar_0 - 2, ar_2)) [ ar_0 >= 1 /\ ar_1 + ar_0 >= 1 /\ ar_1 >= 1 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f2(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0, ar_1, ar_2)) 3.74/1.88 3.74/1.88 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(f2(ar_0, ar_1, ar_2)) [ 0 <= 0 ] 3.74/1.88 3.74/1.88 start location: koat_start 3.74/1.88 3.74/1.88 leaf cost: 0 3.74/1.88 3.74/1.88 3.74/1.88 3.74/1.88 Repeatedly propagating knowledge in problem 2 produces the following problem: 3.74/1.88 3.74/1.88 3: T: 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ 0 >= ar_1 ] 3.74/1.88 3.74/1.88 (Comp: 1, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f1(ar_0, ar_1, d)) [ ar_1 >= 1 /\ 0 >= ar_0 ] 3.74/1.88 3.74/1.88 (Comp: ?, Cost: 1) f300(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0 - 1, ar_0 - 2, ar_2)) [ ar_0 >= 1 /\ ar_1 + ar_0 >= 1 /\ ar_1 >= 1 ] 3.74/1.88 3.74/1.88 (Comp: 1, Cost: 1) f2(ar_0, ar_1, ar_2) -> Com_1(f300(ar_0, ar_1, ar_2)) 3.74/1.88 3.74/1.88 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2) -> Com_1(f2(ar_0, ar_1, ar_2)) [ 0 <= 0 ] 3.74/1.88 3.74/1.88 start location: koat_start 3.74/1.88 3.74/1.88 leaf cost: 0 3.74/1.88 3.74/1.88
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