details

property	value
status	complete
benchmark	wcet2.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n151.star.cs.uiowa.edu
space	SAS10

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.74484 seconds
cpu usage	6.09897
user time	5.75056
system time	0.348406
max virtual memory	1.8530664E7
max residence set size	231208.0

stage attributes

key	value
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

5.99/2.71 WORST_CASE(Omega(n^1), O(n^1)) 5.99/2.72 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 5.99/2.72 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 5.99/2.72 5.99/2.72 5.99/2.72 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 5.99/2.72 5.99/2.72 (0) CpxIntTrs 5.99/2.72 (1) Koat Proof [FINISHED, 404 ms] 5.99/2.72 (2) BOUNDS(1, n^1) 5.99/2.72 (3) Loat Proof [FINISHED, 1008 ms] 5.99/2.72 (4) BOUNDS(n^1, INF) 5.99/2.72 5.99/2.72 5.99/2.72 ---------------------------------------- 5.99/2.72 5.99/2.72 (0) 5.99/2.72 Obligation: 5.99/2.72 Complexity Int TRS consisting of the following rules: 5.99/2.72 start(A, B, C, D, E, F, G, H) -> Com_1(stop(A, B, C, D, E, F, G, H)) :|: A >= 5 && B >= C && B <= C && D >= E && D <= E && F >= G && F <= G && H >= A && H <= A 5.99/2.72 start(A, B, C, D, E, F, G, H) -> Com_1(lbl92(A, B, C, H, E, 0, G, 1 + H)) :|: 2 >= A && B >= C && B <= C && D >= E && D <= E && F >= G && F <= G && H >= A && H <= A 5.99/2.72 start(A, B, C, D, E, F, G, H) -> Com_1(lbl82(A, 0, C, D, E, 1, G, H)) :|: A >= 3 && 4 >= A && B >= C && B <= C && D >= E && D <= E && F >= G && F <= G && H >= A && H <= A 5.99/2.72 lbl92(A, B, C, D, E, F, G, H) -> Com_1(stop(A, B, C, D, E, F, G, H)) :|: D >= 4 && D >= A && F + 10 >= 5 * D && F >= 0 && H >= D + 1 && H <= D + 1 5.99/2.72 lbl92(A, B, C, D, E, F, G, H) -> Com_1(lbl92(A, B, C, H, E, 0, G, 1 + H)) :|: 1 >= D && D >= A && F + 10 >= 5 * D && F >= 0 && H >= D + 1 && H <= D + 1 5.99/2.72 lbl92(A, B, C, D, E, F, G, H) -> Com_1(lbl82(A, 0, C, D, E, 1, G, H)) :|: D >= 2 && 3 >= D && D >= A && F + 10 >= 5 * D && F >= 0 && H >= D + 1 && H <= D + 1 5.99/2.72 lbl82(A, B, C, D, E, F, G, H) -> Com_1(lbl92(A, B, C, H, E, F, G, 1 + H)) :|: 2 >= H && 9 >= B && B >= 0 && H >= A && H >= 3 && 4 >= H && F >= B + 1 && F <= B + 1 5.99/2.72 lbl82(A, B, C, D, E, F, G, H) -> Com_1(lbl92(A, B, C, H, E, F, G, 1 + H)) :|: H >= A && H >= 3 && 4 >= H && F >= 10 && F <= 10 && B >= 9 && B <= 9 5.99/2.72 lbl82(A, B, C, D, E, F, G, H) -> Com_1(lbl82(A, F, C, D, E, 1 + F, G, H)) :|: H >= 3 && 8 >= B && 9 >= B && B >= 0 && H >= A && 4 >= H && F >= B + 1 && F <= B + 1 5.99/2.72 start0(A, B, C, D, E, F, G, H) -> Com_1(start(A, C, C, E, E, G, G, A)) :|: TRUE 5.99/2.72 5.99/2.72 The start-symbols are:[start0_8] 5.99/2.72 5.99/2.72 5.99/2.72 ---------------------------------------- 5.99/2.72 5.99/2.72 (1) Koat Proof (FINISHED) 5.99/2.72 YES(?, 44*ar_0 + 221) 5.99/2.72 5.99/2.72 5.99/2.72 5.99/2.72 Initial complexity problem: 5.99/2.72 5.99/2.72 1: T: 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ ar_0 >= 5 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, 0, ar_6, ar_7 + 1)) [ 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, 0, ar_2, ar_3, ar_4, 1, ar_6, ar_7)) [ ar_0 >= 3 /\ 4 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ ar_3 >= 4 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, 0, ar_6, ar_7 + 1)) [ 1 >= ar_3 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, 0, ar_2, ar_3, ar_4, 1, ar_6, ar_7)) [ ar_3 >= 2 /\ 3 >= ar_3 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, ar_5, ar_6, ar_7 + 1)) [ 2 >= ar_7 /\ 9 >= ar_1 /\ ar_1 >= 0 /\ ar_7 >= ar_0 /\ ar_7 >= 3 /\ 4 >= ar_7 /\ ar_5 = ar_1 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, ar_5, ar_6, ar_7 + 1)) [ ar_7 >= ar_0 /\ ar_7 >= 3 /\ 4 >= ar_7 /\ ar_5 = 10 /\ ar_1 = 9 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, ar_5, ar_2, ar_3, ar_4, ar_5 + 1, ar_6, ar_7)) [ ar_7 >= 3 /\ 8 >= ar_1 /\ 9 >= ar_1 /\ ar_1 >= 0 /\ ar_7 >= ar_0 /\ 4 >= ar_7 /\ ar_5 = ar_1 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(start(ar_0, ar_2, ar_2, ar_4, ar_4, ar_6, ar_6, ar_0)) 5.99/2.72 5.99/2.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ 0 <= 0 ] 5.99/2.72 5.99/2.72 start location: koat_start 5.99/2.72 5.99/2.72 leaf cost: 0 5.99/2.72 5.99/2.72 5.99/2.72 5.99/2.72 Testing for reachability in the complexity graph removes the following transition from problem 1: 5.99/2.72 5.99/2.72 lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, ar_5, ar_6, ar_7 + 1)) [ 2 >= ar_7 /\ 9 >= ar_1 /\ ar_1 >= 0 /\ ar_7 >= ar_0 /\ ar_7 >= 3 /\ 4 >= ar_7 /\ ar_5 = ar_1 + 1 ] 5.99/2.72 5.99/2.72 We thus obtain the following problem: 5.99/2.72 5.99/2.72 2: T: 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ ar_3 >= 4 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, ar_5, ar_6, ar_7 + 1)) [ ar_7 >= ar_0 /\ ar_7 >= 3 /\ 4 >= ar_7 /\ ar_5 = 10 /\ ar_1 = 9 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl82(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, ar_5, ar_2, ar_3, ar_4, ar_5 + 1, ar_6, ar_7)) [ ar_7 >= 3 /\ 8 >= ar_1 /\ 9 >= ar_1 /\ ar_1 >= 0 /\ ar_7 >= ar_0 /\ 4 >= ar_7 /\ ar_5 = ar_1 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, 0, ar_2, ar_3, ar_4, 1, ar_6, ar_7)) [ ar_3 >= 2 /\ 3 >= ar_3 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) lbl92(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, 0, ar_6, ar_7 + 1)) [ 1 >= ar_3 /\ ar_3 >= ar_0 /\ ar_5 + 10 >= 5*ar_3 /\ ar_5 >= 0 /\ ar_7 = ar_3 + 1 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl82(ar_0, 0, ar_2, ar_3, ar_4, 1, ar_6, ar_7)) [ ar_0 >= 3 /\ 4 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(lbl92(ar_0, ar_1, ar_2, ar_7, ar_4, 0, ar_6, ar_7 + 1)) [ 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ ar_0 >= 5 /\ ar_1 = ar_2 /\ ar_3 = ar_4 /\ ar_5 = ar_6 /\ ar_7 = ar_0 ] 5.99/2.72 5.99/2.72 (Comp: ?, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(start(ar_0, ar_2, ar_2, ar_4, ar_4, ar_6, ar_6, ar_0)) 5.99/2.72 5.99/2.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5, ar_6, ar_7)) [ 0 <= 0 ] 5.99/2.72 popout

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all output return to Complexity_ITS 2019-03-21 04.46