details

property	value
status	complete
benchmark	wise.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n002.star.cs.uiowa.edu
space	WTC

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.36635 seconds
cpu usage	4.93682
user time	4.67322
system time	0.263594
max virtual memory	1.8532412E7
max residence set size	220212.0

stage attributes

key	value
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

4.82/2.32 WORST_CASE(Omega(n^1), O(n^1)) 4.89/2.33 proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat 4.89/2.33 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.89/2.33 4.89/2.33 4.89/2.33 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 4.89/2.33 4.89/2.33 (0) CpxIntTrs 4.89/2.33 (1) Koat Proof [FINISHED, 205 ms] 4.89/2.33 (2) BOUNDS(1, n^1) 4.89/2.33 (3) Loat Proof [FINISHED, 630 ms] 4.89/2.33 (4) BOUNDS(n^1, INF) 4.89/2.33 4.89/2.33 4.89/2.33 ---------------------------------------- 4.89/2.33 4.89/2.33 (0) 4.89/2.33 Obligation: 4.89/2.33 Complexity Int TRS consisting of the following rules: 4.89/2.33 evalwisestart(A, B) -> Com_1(evalwiseentryin(A, B)) :|: TRUE 4.89/2.33 evalwiseentryin(A, B) -> Com_1(evalwisereturnin(A, B)) :|: 0 >= A + 1 4.89/2.33 evalwiseentryin(A, B) -> Com_1(evalwisereturnin(A, B)) :|: 0 >= B + 1 4.89/2.33 evalwiseentryin(A, B) -> Com_1(evalwisebb6in(B, A)) :|: A >= 0 && B >= 0 4.89/2.33 evalwisebb6in(A, B) -> Com_1(evalwisebb3in(A, B)) :|: B >= A + 3 4.89/2.33 evalwisebb6in(A, B) -> Com_1(evalwisebb3in(A, B)) :|: A >= B + 3 4.89/2.33 evalwisebb6in(A, B) -> Com_1(evalwisereturnin(A, B)) :|: 2 + A >= B && 2 + B >= A 4.89/2.33 evalwisebb3in(A, B) -> Com_1(evalwisebb4in(A, B)) :|: A >= B + 1 4.89/2.33 evalwisebb3in(A, B) -> Com_1(evalwisebb5in(A, B)) :|: B >= A 4.89/2.33 evalwisebb4in(A, B) -> Com_1(evalwisebb6in(A, B + 1)) :|: TRUE 4.89/2.33 evalwisebb5in(A, B) -> Com_1(evalwisebb6in(A + 1, B)) :|: TRUE 4.89/2.33 evalwisereturnin(A, B) -> Com_1(evalwisestop(A, B)) :|: TRUE 4.89/2.33 4.89/2.33 The start-symbols are:[evalwisestart_2] 4.89/2.33 4.89/2.33 4.89/2.33 ---------------------------------------- 4.89/2.33 4.89/2.33 (1) Koat Proof (FINISHED) 4.89/2.33 YES(?, 18*ar_1 + 18*ar_0 + 20) 4.89/2.33 4.89/2.33 4.89/2.33 4.89/2.33 Initial complexity problem: 4.89/2.33 4.89/2.33 1: T: 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisestart(ar_0, ar_1) -> Com_1(evalwiseentryin(ar_0, ar_1)) 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ 0 >= ar_0 + 1 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ 0 >= ar_1 + 1 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisebb6in(ar_1, ar_0)) [ ar_0 >= 0 /\ ar_1 >= 0 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisebb3in(ar_0, ar_1)) [ ar_1 >= ar_0 + 3 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 + 3 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ ar_0 + 2 >= ar_1 /\ ar_1 + 2 >= ar_0 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb3in(ar_0, ar_1) -> Com_1(evalwisebb4in(ar_0, ar_1)) [ ar_0 >= ar_1 + 1 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb3in(ar_0, ar_1) -> Com_1(evalwisebb5in(ar_0, ar_1)) [ ar_1 >= ar_0 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb4in(ar_0, ar_1) -> Com_1(evalwisebb6in(ar_0, ar_1 + 1)) 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb5in(ar_0, ar_1) -> Com_1(evalwisebb6in(ar_0 + 1, ar_1)) 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisereturnin(ar_0, ar_1) -> Com_1(evalwisestop(ar_0, ar_1)) 4.89/2.33 4.89/2.33 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalwisestart(ar_0, ar_1)) [ 0 <= 0 ] 4.89/2.33 4.89/2.33 start location: koat_start 4.89/2.33 4.89/2.33 leaf cost: 0 4.89/2.33 4.89/2.33 4.89/2.33 4.89/2.33 Repeatedly propagating knowledge in problem 1 produces the following problem: 4.89/2.33 4.89/2.33 2: T: 4.89/2.33 4.89/2.33 (Comp: 1, Cost: 1) evalwisestart(ar_0, ar_1) -> Com_1(evalwiseentryin(ar_0, ar_1)) 4.89/2.33 4.89/2.33 (Comp: 1, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ 0 >= ar_0 + 1 ] 4.89/2.33 4.89/2.33 (Comp: 1, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ 0 >= ar_1 + 1 ] 4.89/2.33 4.89/2.33 (Comp: 1, Cost: 1) evalwiseentryin(ar_0, ar_1) -> Com_1(evalwisebb6in(ar_1, ar_0)) [ ar_0 >= 0 /\ ar_1 >= 0 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisebb3in(ar_0, ar_1)) [ ar_1 >= ar_0 + 3 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 + 3 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb6in(ar_0, ar_1) -> Com_1(evalwisereturnin(ar_0, ar_1)) [ ar_0 + 2 >= ar_1 /\ ar_1 + 2 >= ar_0 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb3in(ar_0, ar_1) -> Com_1(evalwisebb4in(ar_0, ar_1)) [ ar_0 >= ar_1 + 1 ] 4.89/2.33 4.89/2.33 (Comp: ?, Cost: 1) evalwisebb3in(ar_0, ar_1) -> Com_1(evalwisebb5in(ar_0, ar_1)) [ ar_1 >= ar_0 ] 4.89/2.33 popout

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all output return to Complexity_ITS 2019-03-21 04.46