details

property	value
status	complete
benchmark	SequentialSingle.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n119.star.cs.uiowa.edu
space	POPL09

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.12744 seconds
cpu usage	4.55187
user time	4.29285
system time	0.259015
max virtual memory	1.8529112E7
max residence set size	220592.0

stage attributes

key	value
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

4.45/2.10 WORST_CASE(Omega(n^1), O(n^1)) 4.45/2.11 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 4.45/2.11 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.45/2.11 4.45/2.11 4.45/2.11 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 4.45/2.11 4.45/2.11 (0) CpxIntTrs 4.45/2.11 (1) Koat Proof [FINISHED, 11 ms] 4.45/2.11 (2) BOUNDS(1, n^1) 4.45/2.11 (3) Loat Proof [FINISHED, 549 ms] 4.45/2.11 (4) BOUNDS(n^1, INF) 4.45/2.11 4.45/2.11 4.45/2.11 ---------------------------------------- 4.45/2.11 4.45/2.11 (0) 4.45/2.11 Obligation: 4.45/2.11 Complexity Int TRS consisting of the following rules: 4.45/2.11 evalSequentialSinglestart(A, B) -> Com_1(evalSequentialSingleentryin(A, B)) :|: TRUE 4.45/2.11 evalSequentialSingleentryin(A, B) -> Com_1(evalSequentialSinglebb1in(0, B)) :|: TRUE 4.45/2.11 evalSequentialSinglebb1in(A, B) -> Com_1(evalSequentialSinglebb5in(A, B)) :|: A >= B 4.45/2.11 evalSequentialSinglebb1in(A, B) -> Com_1(evalSequentialSinglebb2in(A, B)) :|: B >= A + 1 4.45/2.11 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebbin(A, B)) :|: 0 >= C + 1 4.45/2.11 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebbin(A, B)) :|: C >= 1 4.45/2.11 evalSequentialSinglebb2in(A, B) -> Com_1(evalSequentialSinglebb5in(A, B)) :|: TRUE 4.45/2.11 evalSequentialSinglebbin(A, B) -> Com_1(evalSequentialSinglebb1in(A + 1, B)) :|: TRUE 4.45/2.11 evalSequentialSinglebb5in(A, B) -> Com_1(evalSequentialSinglebb4in(A, B)) :|: B >= A + 1 4.45/2.11 evalSequentialSinglebb5in(A, B) -> Com_1(evalSequentialSinglereturnin(A, B)) :|: A >= B 4.45/2.11 evalSequentialSinglebb4in(A, B) -> Com_1(evalSequentialSinglebb5in(A + 1, B)) :|: TRUE 4.45/2.11 evalSequentialSinglereturnin(A, B) -> Com_1(evalSequentialSinglestop(A, B)) :|: TRUE 4.45/2.11 4.45/2.11 The start-symbols are:[evalSequentialSinglestart_2] 4.45/2.11 4.45/2.11 4.45/2.11 ---------------------------------------- 4.45/2.11 4.45/2.11 (1) Koat Proof (FINISHED) 4.45/2.11 YES(?, 7*ar_1 + 21) 4.45/2.11 4.45/2.11 4.45/2.11 4.45/2.11 Initial complexity problem: 4.45/2.11 4.45/2.11 1: T: 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglestart(ar_0, ar_1) -> Com_1(evalSequentialSingleentryin(ar_0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSingleentryin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ 0 >= c + 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ c >= 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebbin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(ar_0 + 1, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb5in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb4in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb5in(ar_0, ar_1) -> Com_1(evalSequentialSinglereturnin(ar_0, ar_1)) [ ar_0 >= ar_1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb4in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0 + 1, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglereturnin(ar_0, ar_1) -> Com_1(evalSequentialSinglestop(ar_0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalSequentialSinglestart(ar_0, ar_1)) [ 0 <= 0 ] 4.45/2.11 4.45/2.11 start location: koat_start 4.45/2.11 4.45/2.11 leaf cost: 0 4.45/2.11 4.45/2.11 4.45/2.11 4.45/2.11 Repeatedly propagating knowledge in problem 1 produces the following problem: 4.45/2.11 4.45/2.11 2: T: 4.45/2.11 4.45/2.11 (Comp: 1, Cost: 1) evalSequentialSinglestart(ar_0, ar_1) -> Com_1(evalSequentialSingleentryin(ar_0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: 1, Cost: 1) evalSequentialSingleentryin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb1in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ 0 >= c + 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebbin(ar_0, ar_1)) [ c >= 1 ] 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb2in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb5in(ar_0, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebbin(ar_0, ar_1) -> Com_1(evalSequentialSinglebb1in(ar_0 + 1, ar_1)) 4.45/2.11 4.45/2.11 (Comp: ?, Cost: 1) evalSequentialSinglebb5in(ar_0, ar_1) -> Com_1(evalSequentialSinglebb4in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 4.45/2.11 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Complexity_ITS 2019-03-21 04.46