details

property	value
status	complete
benchmark	10.koat
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n017.star.cs.uiowa.edu
space	Beerendonk

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	2.76348 seconds
cpu usage	5.49056
user time	5.21747
system time	0.273088
max virtual memory	1.8534436E7
max residence set size	224292.0

stage attributes

key	value
starexec-result	WORST_CASE(?, O(n^1))

output

5.36/2.72 WORST_CASE(?, O(n^1)) 5.36/2.73 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 5.36/2.73 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 5.36/2.73 5.36/2.73 5.36/2.73 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, max(1, 1 + 2 * Arg_0) + nat(Arg_0)). 5.36/2.73 5.36/2.73 (0) CpxIntTrs 5.36/2.73 (1) Koat2 Proof [FINISHED, 718 ms] 5.36/2.73 (2) BOUNDS(1, max(1, 1 + 2 * Arg_0) + nat(Arg_0)) 5.36/2.73 5.36/2.73 5.36/2.73 ---------------------------------------- 5.36/2.73 5.36/2.73 (0) 5.36/2.73 Obligation: 5.36/2.73 Complexity Int TRS consisting of the following rules: 5.36/2.73 eval(A) -> Com_1(eval(0)) :|: 2 * B >= 0 && 0 >= 2 * B && A >= 1 && A <= 1 5.36/2.73 eval(A) -> Com_1(eval(2 * B)) :|: 2 * B >= 0 && 2 + 2 * B >= 0 && A >= 1 + 2 * B && A <= 1 + 2 * B 5.36/2.73 eval(A) -> Com_1(eval(B)) :|: 1 >= 2 * C && 2 * C >= 0 && 2 * D >= 1 && 1 >= 2 * D && 1 >= 2 * E && 3 * E >= 2 && B >= E && 1 >= 2 * F && 3 * F >= 2 && F >= B && A >= 1 && A <= 1 5.36/2.73 eval(A) -> Com_1(eval(B)) :|: 2 * D >= 1 && 1 + 2 * D >= 0 && 2 * D >= 2 * C && 1 + 2 * C >= 2 * D && 2 * D >= 2 * E && 3 * E >= 2 * D + 1 && B >= E && 2 * D >= 2 * F && 3 * F >= 2 * D + 1 && F >= B && A >= 2 * D && A <= 2 * D 5.36/2.73 start(A) -> Com_1(eval(A)) :|: TRUE 5.36/2.73 5.36/2.73 The start-symbols are:[start_1] 5.36/2.73 5.36/2.73 5.36/2.73 ---------------------------------------- 5.36/2.73 5.36/2.73 (1) Koat2 Proof (FINISHED) 5.36/2.73 YES( ?, 1+2*max([0, Arg_0])+max([0, Arg_0]) {O(n)}) 5.36/2.73 5.36/2.73 5.36/2.73 5.36/2.73 Initial Complexity Problem: 5.36/2.73 5.36/2.73 Start: start 5.36/2.73 5.36/2.73 Program_Vars: Arg_0 5.36/2.73 5.36/2.73 Temp_Vars: B, C, D, E, F 5.36/2.73 5.36/2.73 Locations: eval, start 5.36/2.73 5.36/2.73 Transitions: 5.36/2.73 5.36/2.73 eval(Arg_0) -> eval(0):|:0 <= (2)*B && (2)*B <= 0 && Arg_0 <= 1 && 1 <= Arg_0 5.36/2.73 5.36/2.73 eval(Arg_0) -> eval((2)*B):|:0 <= (2)*B && 0 <= 2+(2)*B && Arg_0 <= 1+(2)*B && 1+(2)*B <= Arg_0 5.36/2.73 5.36/2.73 eval(Arg_0) -> eval(B):|:1 <= (2)*C && 0 <= 1+(2)*C && (2)*D <= (2)*C && (2)*C <= 1+(2)*D && (2)*E <= (2)*C && (2)*C+1 <= (3)*E && E <= B && (2)*F <= (2)*C && (2)*C+1 <= (3)*F && B <= F && Arg_0 <= (2)*C && (2)*C <= Arg_0 5.36/2.73 5.36/2.73 start(Arg_0) -> eval(Arg_0):|: 5.36/2.73 5.36/2.73 5.36/2.73 5.36/2.73 Timebounds: 5.36/2.73 5.36/2.73 Overall timebound: 1+2*max([0, Arg_0])+max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 0: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 1: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 3: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 4: start->eval: 1 {O(1)} 5.36/2.73 5.36/2.73 5.36/2.73 5.36/2.73 Costbounds: 5.36/2.73 5.36/2.73 Overall costbound: 1+2*max([0, Arg_0])+max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 0: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 1: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 3: eval->eval: max([0, Arg_0]) {O(n)} 5.36/2.73 5.36/2.73 4: start->eval: 1 {O(1)} 5.36/2.73 5.36/2.73 5.36/2.73 5.36/2.73 Sizebounds: 5.36/2.73 5.36/2.73 `Lower: 5.36/2.73 5.36/2.73 0: eval->eval, Arg_0: 0 {O(1)} 5.36/2.73 5.36/2.73 1: eval->eval, Arg_0: 0 {O(1)} 5.36/2.73 5.36/2.73 3: eval->eval, Arg_0: 1 {O(1)} 5.36/2.73 5.36/2.73 4: start->eval, Arg_0: Arg_0 {O(n)} 5.36/2.73 5.36/2.73 `Upper: 5.36/2.73 5.36/2.73 0: eval->eval, Arg_0: 0 {O(1)} 5.36/2.73 5.36/2.73 4: start->eval, Arg_0: Arg_0 {O(n)} popout

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job log

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actions

all output return to Complexity_ITS 2019-03-21 04.46