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Complexity_ITS 2019-03-21 04.46 pair #429991246
details
property
value
status
complete
benchmark
mspe.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n123.star.cs.uiowa.edu
space
misc
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
3.72943 seconds
cpu usage
8.04883
user time
7.70829
system time
0.340541
max virtual memory
1.8659512E7
max residence set size
221852.0
stage attributes
key
value
starexec-result
WORST_CASE(Omega(n^1), O(n^1))
output
7.76/3.70 WORST_CASE(Omega(n^1), O(n^1)) 8.01/3.71 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 8.01/3.71 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 8.01/3.71 8.01/3.71 8.01/3.71 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 8.01/3.71 8.01/3.71 (0) CpxIntTrs 8.01/3.71 (1) Koat Proof [FINISHED, 208 ms] 8.01/3.71 (2) BOUNDS(1, n^1) 8.01/3.71 (3) Loat Proof [FINISHED, 1994 ms] 8.01/3.71 (4) BOUNDS(n^1, INF) 8.01/3.71 8.01/3.71 8.01/3.71 ---------------------------------------- 8.01/3.71 8.01/3.71 (0) 8.01/3.71 Obligation: 8.01/3.71 Complexity Int TRS consisting of the following rules: 8.01/3.71 start(A, B, C, D, E, F) -> Com_1(m1(A, B, C, D, E, F)) :|: A >= 0 && B + A + 2 >= 2 * C && B >= A + 1 && 2 * C >= B + A && D >= 0 && E + 1 >= C && E + 1 <= C && F >= A && F <= A 8.01/3.71 m1(A, B, C, D, E, F) -> Com_1(m1(A, B, H, D, E, G)) :|: B >= 1 && D >= 0 && A >= E + 1 && B + 1 >= G && C + 1 >= H && H >= 1 + C && F + 1 >= G && G >= 1 + F 8.01/3.71 m1(A, B, C, D, E, F) -> Com_1(m1(H, B, C, D, E, G)) :|: B >= 1 && D >= 0 && B >= F && E + 1 >= H && C >= B + 1 && F + 1 >= G && G >= 1 + F && A + 1 >= H && H >= 1 + A 8.01/3.71 m1(A, B, C, D, E, F) -> Com_1(m1(A, B, H, D, E, G)) :|: B >= 1 && D >= 0 && B >= F && B + 1 >= H && E >= A && F + 1 >= G && G >= 1 + F && C + 1 >= H && H >= 1 + C 8.01/3.71 m1(A, B, C, D, E, F) -> Com_1(m1(H, B, C, D, E, G)) :|: B >= 1 && D >= 0 && B >= F && B >= C && E + 1 >= H && A + 1 >= H && H >= 1 + A && F + 1 >= G && G >= 1 + F 8.01/3.71 8.01/3.71 The start-symbols are:[start_6] 8.01/3.71 8.01/3.71 8.01/3.71 ---------------------------------------- 8.01/3.71 8.01/3.71 (1) Koat Proof (FINISHED) 8.01/3.71 YES(?, 4*ar_1 + 5) 8.01/3.71 8.01/3.71 8.01/3.71 8.01/3.71 Initial complexity problem: 8.01/3.71 8.01/3.71 1: T: 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5)) [ ar_0 >= 0 /\ ar_1 + ar_0 + 2 >= 2*ar_2 /\ ar_1 >= ar_0 + 1 /\ 2*ar_2 >= ar_1 + ar_0 /\ ar_3 >= 0 /\ ar_4 + 1 = ar_2 /\ ar_5 = ar_0 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_0 >= ar_4 + 1 /\ ar_1 >= ar_5 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_4 >= ar_0 /\ ar_2 >= ar_1 + 1 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5)) [ 0 <= 0 ] 8.01/3.71 8.01/3.71 start location: koat_start 8.01/3.71 8.01/3.71 leaf cost: 0 8.01/3.71 8.01/3.71 8.01/3.71 8.01/3.71 Repeatedly propagating knowledge in problem 1 produces the following problem: 8.01/3.71 8.01/3.71 2: T: 8.01/3.71 8.01/3.71 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5)) [ ar_0 >= 0 /\ ar_1 + ar_0 + 2 >= 2*ar_2 /\ ar_1 >= ar_0 + 1 /\ 2*ar_2 >= ar_1 + ar_0 /\ ar_3 >= 0 /\ ar_4 + 1 = ar_2 /\ ar_5 = ar_0 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_0 >= ar_4 + 1 /\ ar_1 >= ar_5 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_4 >= ar_0 /\ ar_2 >= ar_1 + 1 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 (Comp: ?, Cost: 1) m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(start(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5)) [ 0 <= 0 ] 8.01/3.71 8.01/3.71 start location: koat_start 8.01/3.71 8.01/3.71 leaf cost: 0 8.01/3.71 8.01/3.71 8.01/3.71 8.01/3.71 A polynomial rank function with 8.01/3.71 8.01/3.71 Pol(start) = V_2 + 1 8.01/3.71 8.01/3.71 Pol(m1) = V_2 - V_6 + 1 8.01/3.71 8.01/3.71 Pol(koat_start) = V_2 + 1 8.01/3.71 8.01/3.71 orients all transitions weakly and the transitions 8.01/3.71 8.01/3.71 m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_4 >= ar_0 /\ ar_2 >= ar_1 + 1 ] 8.01/3.71 8.01/3.71 m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0 + 1, ar_1, ar_2, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_1 >= ar_5 /\ ar_1 >= ar_2 /\ ar_4 >= ar_0 ] 8.01/3.71 8.01/3.71 m1(ar_0, ar_1, ar_2, ar_3, ar_4, ar_5) -> Com_1(m1(ar_0, ar_1, ar_2 + 1, ar_3, ar_4, ar_5 + 1)) [ ar_1 >= 1 /\ ar_3 >= 0 /\ ar_0 >= ar_4 + 1 /\ ar_1 >= ar_5 ] 8.01/3.71 8.01/3.71 strictly and produces the following problem: 8.01/3.71 8.01/3.71 3: T:
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